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3 years ago

-5a-5b/a+b need help now please!!!!

Mathematics

1 answer:

valentina_108 [34]3 years ago

6 0

Your answer should just be -5

<em>I'm just a few Brainliests away from ranking up, so one would be much appreciated. Thank you!</em>

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Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3

MAXImum [283]

Observe that

$\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v$

In the original equation, divide both sides by $\dfrac12$ :

$-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2$

$\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2$

Next,

$\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi$

where $n$ is any integer. Then

$\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi$

Fix $n=0$ to ensure $-\pi$ , so that

$v=-\dfrac\pi6,v=-\dfrac\pi2$

3 0

4 years ago

Two angles of a quadrilateral measure 130 and 10. The other two angles are in a ratio 2.9. What are the measures of those two a

andrey2020 [161]

Answer:

check: 50+160+130+20 = 360

50:160 = 5 : 16

Step-by-step explanation:et the smaller of the unknown angles be 5x and the larger of the two be 16x

so 130+20+5x+16x = 360

21x = 210

x = 10

so the two missing angles are 50° and 160°

check: 50+160+130+20 = 360

50:160 = 5 : 16

8 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeee

juin [17]

Answer: draw a diagonal line

Step-by-step explanation:

like this:

since it's going up, it's a positive slope

3 0

3 years ago

Read 2 more answers

What is the measure of the missing exterior angle?

larisa86 [58]

Answer:

the missing angle is 148°

Step-by-step explanation:

the sum of all exterior angles of a triangle are 360°

so, 360-138-74 = 148°

3 0

3 years ago

I need help on distributive property please

Brums [2.3K]

Answer:

Could you put the questions please?

Step-by-step explanation:

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3 years ago