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Bezzdna [24]
3 years ago
13

find an equation of the tangent line to the curve at the given point. y=sqrt(x) (1,1) Ive never been good with these equations a

nd the square root is confusing me.
Mathematics
1 answer:
Nady [450]3 years ago
4 0
Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ).   In this case: x0=1, y0=1
f´(x)=\frac{1}{2 \sqrt{x} }(Derivation)
f´(x0)=\frac{1}{2}
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =\frac{1}{2}x+ \frac{1}{2}   
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