Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= ![\sqrt{(a-7)^2+(b+2)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28a-7%29%5E2%2B%28b%2B2%29%5E2%7D)
But this distance needs to be betweem 50 & 60
So
![50](https://tex.z-dn.net/?f=50%3C%5Csqrt%7B%28a-7%29%5E2%2B%28b%2B2%29%5E2%7D%3C60)
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= ![\sqrt{(7-7)^2+(50+2)^2}= \sqrt{(52)^2}=52](https://tex.z-dn.net/?f=%5Csqrt%7B%287-7%29%5E2%2B%2850%2B2%29%5E2%7D%3D%20%5Csqrt%7B%2852%29%5E2%7D%3D52)
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π
<h3>The circle with center P</h3>
Given that the circle has a center P
It means that lengths PQ, PR, PS and PT
From the question, we understand that QR = ST.
This implies that triangles QRP and STP are congruent.
i.e. △QRP ≅ △STP is true
<h3>The length of the minor arc</h3>
The given parameters are:
Angle, Ф = 99
Radius, r = 1
The length of the arc is:
L = Ф/360 * 2πr
So, we have:
L = 99/360 * 2π * 1
Evaluate
L = 198/360π
Divide
L = 11/20π
Hence, the length of the minor arc is 11/20π
Read more about circle and arcs at:
brainly.com/question/3652658
#SPJ1
115+(4n-5)=180 115+4n-5=180. 4n=70 n=15
Answer:
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Step-by-step explanation:
Answer:
7 units to the left of 3 is your answer.
Hope this helps!