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2 years ago

What is the square root of 9

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

6 0

The square root of 9 is 3 hope you find this helpful x

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Fourteen less than the product of ten and a number is the sum of twice a number and ten.

iren2701 [21]

Answer:

in what time will 24000 amount to rs.30000 at 10% p.a?

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2 years ago

If ΔEFG ~ ΔLMN with a ratio of 2:1, which of the following is true?

strojnjashka [21]

Answer:

segment EF over segment LM equals segment FG over segment MN

Step-by-step explanation:

The triangles are similar, not congruent, so any answer choice with the word "congruent" can be ignored.

The sequence of letters in the triangle name tells you the corresponding segments:

EF corresponds to LM
EG corresponds to LN
FG corresponds to MN

Corresponding segments have the same ratio, so ...

EF/LM = FG/MN . . . . . . matches the first answer choice

EF/LM = EG/LN . . . . does not match the 3rd answer choice

7 0

2 years ago

Which one is bigger 64 in or 5 ft

anzhelika [568]

64 inches is greater than 5ft. There are 12 inches in a foot. You should divide 64 by 12. You will get 5.333 (repeating, in this instance we will round up to 5.4)

5 0

3 years ago

Read 2 more answers

Find x <br> Plz help me !!!

mel-nik [20]

Answer:

$\Huge\boxed{x=33.2}$

Step-by-step explanation:

Hello there!

We can solve for x using law of sines

As we can see in the image a side length divided by sin ( its opposite angle) = a different side length divided by sin ( its opposite angle)

So we can use this equation to solve for x

$\frac{21}{sin(35)} =\frac{x}{sin(65)}$

Our objective is to isolate the variable using inverse operations so to get rid of sin (65) we multiply each side by sin (65)

$\frac{x}{sin(65)} sin(65)=x\\\\\frac{21}{sin(35)} sin(65)=\frac{21sin(65)}{sin(35)}$

we're left with

$x=\frac{21sin(65)}{sin(35)}\\x=33.18208755$

assuming we have to round the answer would be 33.18 or 33.2

7 0

2 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

7 0

2 years ago