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agasfer [191]
3 years ago
7

The ruby throated hummingbird has a wingbeat of about 200 beats per second about how many wing Beats would a hummingbird have in

three minutes.
Mathematics
1 answer:
Nady [450]3 years ago
4 0
36,000 wing beats

60 sec= 1 minute 60*3=180sec/3minutes

180*200=36,000

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A shirt costs $30 but is on sale for 25% off. How much does the shirt cost after the sale?
FrozenT [24]

Answer:

$22.50

Step-by-step explanation:

Find 25% of 30 and then take away that amount from 30.

6 0
2 years ago
You choose two different songs on a music playlist at random. Out of 80 songs on the playlist, 36 are hip hop songs. The first s
dexar [7]

Answer:

35/79

Step-by-step explanation:

Assuming you can't choose the same song a second time, the probability is 35/79.

If you can choose the same song, the probability is 36/80, which reduces to 9/20.

7 0
3 years ago
Jensen Tire & Auto is in the process of deciding whether to purchase a maintenance contract for its new computer wheel align
sasho [114]

Answer:

Step-by-step explanation:

Hello!

The given data corresponds to the variables

Y:  Annual Maintenance  Expense ($100s)

X: Weekly Usage  (hours)

n= 10

∑X= 253; ∑X²= 7347; \frac{}{X}= ∑X/n= 253/10= 25.3 Hours

∑Y= 346.50; ∑Y²= 13010.75; \frac{}{Y}= ∑Y/n= 346.50/10= 34.65 $100s

∑XY= 9668.5

a)

To estimate the slope and y-intercept you have to apply the following formulas:

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{9668.5-\frac{253*346.5}{10} }{7347-\frac{(253)^2}{10} }= 0.95

a= \frac{}{Y} -b\frac{}{X} = 34.65-0.95*25.3= 10.53

^Y= a + bX

^Y= 10.53 + 0.95X

b)

H₀: β = 0

H₁: β ≠ 0

α:0.05

F= \frac{MS_{Reg}}{MS_{Error}} ~~F_{Df_{Reg}; Df_{Error}}

F= 47.62

p-value: 0.0001

To decide using the p-value you have to compare it against the level of significance:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The decision is to reject the null hypothesis.

At a 5% significance level you can conclude that the average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

b= 0.95 $100s/hours is the variation of the estimated average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

a= 10.53 $ 100s is the value of the average annual maintenance expense of the computer wheel alignment and balancing machine when the weekly usage is zero.

c)

The value that determines the % of the variability of the dependent variable that is explained by the response variable is the coefficient of determination. You can calculate it manually using the formula:

R^2 = \frac{b^2[sumX^2-\frac{(sumX)^2}{n} ]}{[sumY^2-\frac{(sumY)^2}{n} ]} = \frac{0.95^2[7347-\frac{(253)^2}{10} ]}{[13010.75-\frac{(346.50)^2}{10} ]} = 0.86

This means that 86% of the variability of the annual maintenance expense of the computer wheel alignment and balancing machine is explained by the weekly usage under the estimated model ^Y= 10.53 + 0.95X

d)

Without usage, you'd expect the annual maintenance expense to be $1053

If used 100 hours weekly the expected maintenance expense will be 10.53+0.95*100= 105.53 $100s⇒ $10553

If used 1000 hours weekly the expected maintenance expense will be $96053

It is recommendable to purchase the contract only if the weekly usage of the computer is greater than 100 hours weekly.

4 0
2 years ago
Evaluate 81.4 % of 58.81 km Give your answer rounded to 2 DP.
snow_lady [41]

Answer:

47.87

.................

4 0
3 years ago
Maggie’s brother is 3 years younger than twice her age. The sum of their ages is 18. How old is Maggie?
kykrilka [37]

Answer: Maggie is 7 years old.

7 . 2 = 14

14-3=11

11+7=18

Hope this helps!

6 0
3 years ago
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