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dsp73
3 years ago
6

The answer please????

Mathematics
1 answer:
guapka [62]3 years ago
5 0

Answer:

999

Step-by-step explanation:

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Suppose that E and f are two events and that P(E and F)=0.3 and P(E)=0.5. What is P(F/E)?
yanalaym [24]

Answer:

P(F/E) = 0.6

Step-by-step explanation:

If we are given two dependent events A and B such that their chances of occurrence or the probabilities of the events are: P(A) and P(B).

Then the conditional probability that the event B will occur given that A has already occurred is given by the following formula:

P(B/A) = \dfrac{P(A \cap B)}{P(A)}

Here the two events given are E and F.

P(E\ and\ F)\ or\ P(E\cup F) = 0.3

and P(E) = 0.5

As per the above formula that we have already discussed, the formula can be written as:

P(F/E) = \dfrac{P(E \cap F)}{P(E)}\\\Rightarrow P(F/E) = \dfrac{0.3}{0.5}\\\Rightarrow P(F/E) = \dfrac{3}{5}\\\Rightarrow \bold{P(F/E) = 0.6}

4 0
3 years ago
Find the pattern:3,45,49,61,69,9
bija089 [108]

Answer is: add 4 in between every time

Explanation:

in 45 and 49 there is difference of 4

and in the next 61 and 69 the difference is 8

every it adds 4


i hope you get the idea

3 0
4 years ago
A rectangular prism has dimensions of 1/3, 3, and 5/3 in.
julsineya [31]

Answer:

Step-by-step explanation:

The rectangular prism has a volume equal to V=xyz. V=(1/3)3(5/3)=5/3 in^3. The cube has a volume equal to V=s^3. The volume of the cube is equal to the prism when

s^3=(1/3)(3)(5/3)\\ \\ s^3=5/3\\ \\ s=\sqrt[3]{\frac{5}{3}}in\\ \\ s\approx 1.19in

5 0
3 years ago
Suppose that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 poi
AnnZ [28]

Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A)P(X>135) = \\P(Z>0.625)\\=0.0266

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and Var (x-y)=Var(x)+Var(y) = 19

P(X-Y)>5\\\\=1-0.00029\\=0.9997

C) For a group of 3, average has std deviation = \frac{11}{\sqrt{3} } \\=6.351

P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856

3 0
3 years ago
Show your work (organized!) for 2 points. Correct answer for 1 point. -2 - (-6) + (9÷3) . 4 | Please help!!
kaheart [24]
Whaaaat that doesn’t look like you typed right
6 0
3 years ago
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