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Lilit [14]
3 years ago
12

When you're working with a word processing document and you press the Del key, what happens? A. The paragraph you're working on

is deleted. B. The character to the right of the cursor is deleted. C. The entire document is deleted. D. The formatting style is deleted.
Computers and Technology
1 answer:
Bezzdna [24]3 years ago
4 0
Option c. The entire document is deleted




You might be interested in
Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0
3 years ago
Write a Java program to create a class called Cars. The class should include three instance variables: makes (type: String), mod
Fiesta28 [93]

Answer:

Explanation:

This code was written in Java. It creates the Cars class with the requested variables and methods. It also creates the TestCars class which asks the user for the necessary inputs and then creates three Cars objects and passes the input values to the constructors. Finally, it uses the show() method on each object to call the information. A test has been created and the output can be seen in the attached image below.

import java.util.Scanner;

class TestCars{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Car Make: ");

       String make1 = in.next();

       System.out.print("Enter Car Model: ");

       String model1 = in.next();

       System.out.print("Enter Car Year: ");

       int year1 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make2 = in.next();

       System.out.print("Enter Car Model: ");

       String model2 = in.next();

       System.out.print("Enter Car Year: ");

       int year2 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make3 = in.next();

       System.out.print("Enter Car Model: ");

       String model3 = in.next();

       System.out.print("Enter Car Year: ");

       int year3 = in.nextInt();

       Cars car1 = new Cars(make1, model1, year1);

       Cars car2 = new Cars(make2, model2, year2);

       Cars car3 = new Cars(make3, model3, year3);

       car1.show();

       car2.show();

       car3.show();

   }

}

class Cars {

   String makes, models;

   int years;

   public Cars(String makes, String models, int years) {

       this.makes = makes;

       this.models = models;

       this.years = years;

   }

   public void show() {

       System.out.println("Car's make: " + this.makes);

       System.out.println("Car's model: " + this.models);

       System.out.println("Car's year: " + this.years);

   }

}

5 0
3 years ago
The encapsulation unit on the presentation layer of the osi model is
Zielflug [23.3K]
<span>The encapsulation unit on the presentation layer of the OSI model is the Data link layer (2).</span>
7 0
3 years ago
Use the table on the right to convert from binary to decimal.
postnew [5]

Answer:

There is no table, so I can only comment on the statements:

The binary value of decimal 10 is A.  ==> False, however A is a hexadecimal representation of 10.

The binary value of decimal 13 is 1001  ==> False, 13 would be 1101.

The binary value of decimal 15 is 1111.  ==> True.

The binary value of decimal 14 is E. ==> Again E is a hexadecimal representation of 14.

7 0
2 years ago
Read 2 more answers
What adaptation Judy and her parents have that help them run from predators coming?​
Elza [17]

Answer:

.57

Explanation:

3 0
3 years ago
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