We know that
surface area of the cone (SA)=pi*r²+pi*r*l
where
r is the radius
l is the slant height
SA=306*pi cm²
diameter=12 cm
r=12/2----> r=6 cm
SA=pi*r²+pi*r*l--------> [SA-pi*r²]=pi*r*l----> l=[SA-pi*r²]/[pi*r]
l=[306*pi-pi*6²]/[pi*6]---> [306*pi-36*pi]/[6*pi]---> 45 cm
the answer is
<span>the length of the slant height is </span>45 cm
9514 1404 393
Answer:
x = 28
Step-by-step explanation:
The marked angles are supplementary, so you have ...
(3x +10) +(3x +2) = 180
6x +12 = 180 . . . . . . . . . . simplify
x +2 = 30 . . . . . . . . divide by 6
x = 28 . . . . . . . subtract 2
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<em>Additional comment</em>
You might generally solve a 2-step linear equation by doing the subtraction first, then the division by the coefficient of the variable. If all of the numbers are a multiple of that coefficient, I like to do the division as soon as I can. That way, the numbers I'm working with are as small as possible, and once I isolate the variable term, I have the answer.
The obtuse angle (on the left) is 94°; the acute angle is 86°.
We have that
3 = 3 + 0i -----------> rewrite as 3(1 + 0i)
<span>So now what we have to do is figure out which of the above expressions has cos a = 1 and sin a = 0. </span>
<span>cos 0 = 1, and sin 0 = 0, so that's the answer that we want.
</span><span>the answer is: </span>
3 = 3(cos 0 + i sin 0)
6x+2=2x-2
6x+2-2=2x-2-2
6x=2x-4
6x-2x=2x-4-2x
4x=-4
4x/4= -4/4
x= -1
hope this helps :)
Answer:
Part 1)
Projection of vector A on vector B equals 19 units
Part 2)
Projection of vector B' on vector A' equals 35 units
Step-by-step explanation:
For 2 vectors A and B the projection of A on B is given by the vector dot product of vector A and B
Given
Similarly vector B is written as
Thus the vector dot product of the 2 vectors is obtained as
Part 2)
Given vector A' as
Similarly vector B' is written as
Thus the vector dot product of the 2 vectors is obtained as
