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Suppose you have a large coffee can full of pennies. How can you estimate how much money that can contains without counting all

Yuki888 [10]

If you know how much a penny weighs then you can weigh any amount of pennies and take that weight and divide by the weight of one penny, to get how many there are without counting all the coins.

3 0

3 years ago

Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 10

igomit [66]

Answer:

The confidence interval has an lower limit of $\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ and an upper limit of $\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ , in which $\pi$ is the sample proportion and $n$ is the size of the sample.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$

The confidence interval has an lower limit of $\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ and an upper limit of $\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}$ , in which $\pi$ is the sample proportion and $n$ is the size of the sample.

8 0

4 years ago

a 42 inch diameter tablecloth that hangs off the edge 8 inches. what is the area of the tablecloth use 3.14 for pi

joja [24]

Answer: 1384.74

Step-by-step explanation:

A=πr^2

radius=42/2=21

(3.14)(21)^2

3.14(441)

1384.74

3 0

3 years ago

HELP ILL MARK YOU BRAINLIST write in y=mx+b form HELP ILL MARK YOU BRAINLIST write in y=mx+b form

AnnyKZ [126]

Answer:

im pretty sure it is.

y=-1/4x +3

Good luck!

3 0

3 years ago

Read 2 more answers

A cricular arena is lit by 5 lights equally spaced around the perimeter of the arena. What is the measure of each angle formed b

Kitty [74]

Answer:

108°

Step-by-step explanation:

Suppose that circle with center A is a circular arena. Points B, C, D, E and F are 5 lights. These 5 points form regular pentagon (because these 5 lights are equally spaced around the perimeter of the arena).

The sum of all interior angles of pentagon can be calculated using following formula

$(n-2)\cdot 180^{\circ},\\ \\(5-2)\cdot 180^{\circ}=3\cdot 180^{\circ}=540^{\circ}$

All interior angles in regular pentagon are of equal measure, so

$\dfrac{540^{\circ}}{5}=108^{\circ}$

Thus, the measure of each angle formed by the lights on the perimeter is 108°.

7 0

4 years ago