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3 years ago

6

Destiny has 6 library books on her desk. One third of them are about animals. How many of Destiny’s library books are about anim

als? Draw a diagram to show your work.

1 answer:

Marta_Voda [28]3 years ago

3 0

| shade | | | Each rectangle stands for one third so shade
| this | | | only one rectangle.
| one | | | And one rectangle has two books in it (you
| | | | divide 6 by 3 to get 2).
| | | |
| | | |
| | | |

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olasank [31]

Answer:

3sqrt2

Step-by-step explanation:

If a side length is a, then a^2 + a^2 = 36

2a^2 = 36

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3 years ago

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Step-by-step explanation:

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2 years ago

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kicyunya [14]

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Step-by-step explanation:

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2 years ago

The mean of a population being sampled is 64, and the standard deviation is 6. If the sample size is 50, the standard error of t

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3 years ago

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.3. (Round your ans

Maurinko [17]

Answer:

0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 50

Standard Deviation, σ = 1.3

Sample size, n = 12

We are given that the distribution of hardness of pins is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{1.3}{\sqrt{12}} = 0.3753$

P(sample mean hardness for a random sample of 12 pins is at least 51)

$P( x \geq 51) = P( z \geq \displaystyle\frac{51 - 50}{0.3753}) = P(z \geq 2.6645)$

$= 1 - P(z < 2.6645)$

Calculation the value from standard normal z table, we have,

$P(x \geq 51) = 1 - 0.9961= 0.0039$

0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.

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3 years ago