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3 years ago

Help! I'm so confused

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

5 0

An integer is like a whole number (28 is an integer).
Irrational means the decimal goes on forever.......and cannot be written as a fraction (0.9857... is irrational).
A number that is not real is the squareroot of a negative, or something times i, or dividing by zero (5/0 is unreal).
A rational number can be written as a fraction (like 8 and 1/7).

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What +2/3=11/12 equation

Luden [163]

Answer:

1/4

Step-by-step explanation:

1st: you need to make a common denominator for 2/3 and 11/12 that would be 12, so you would keep 11/12 how it is but multiply the numerator and the denominator by 4 to get it to 12.

You would have ;

8/12+___=11/12

Then just do 11/12-8/12

so that would simplify out to 1/4

6 0

4 years ago

Read 2 more answers

(PLESE HELP) Factor the following expression. Simplify your answer.

mars1129 [50]

The factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

$5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$

Since $(p + 2)^{\frac{1}{3} }$ is common, we factor it out. So, we have

$(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2} + 4)$

Expanding the bracket, we have

$(p + 2)^{\frac{2}{3} } (5p(p^{2} + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

So, the factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

Learn more about factorization here:

brainly.com/question/11579257

#SPJ1

8 0

2 years ago

van someone please help me with this i dont need an explaination i just need a. b. c. or d. please and thank you

Talja [164]

Answer:

option C

$f(x)=-\sqrt{x+3}+8$

Step-by-step explanation:

we have

$f(x)=-2\sqrt{x-3}+8$

using a graphing tool

see the attached figure N $1$

The range is the interval--------> (-∞,8]

$y\leq 8$

case A) $f(x)=\sqrt{x-3}-8$

using a graphing tool

The range is the interval--------> [-8,∞)

$y\geq -8$

case B) $f(x)=\sqrt{x-3}+8$

using a graphing tool

The range is the interval--------> [8,∞)

$y\geq 8$

case C) $f(x)=-\sqrt{x+3}+8$

using a graphing tool

The range is the interval--------> (-∞,8]

$y\leq 8$

case D) $f(x)=-\sqrt{x-3}-8$

using a graphing tool

The range is the interval--------> (-∞,-8]

$y\leq -8$

5 0

3 years ago

Solve the following system by any method. –8x – 8y = 0 –8x + 2y = –20

madam [21]

This one is simple since we already have the two x variables.equal. All we have to do is subtract the equations from one another to get the answer.
So i will subtract the left side by the other left side and the right side by the other right side

-8x - 8y -(-8x + 2y) = 0 -(-20)

distribute negative sign

-8x - 8y + 8x - 2y = 0 + 20

do the math
- 10y = 20
Y = -2

plug t into an equation
-8x -8 (-2) = 0

-8x + 16 = 0
-8x = -16
x = 2
answer (2, -2)

8 0

3 years ago

Please help me!!!!!!!!

zavuch27 [327]

Are you kidding are you sure you want this

3 0

3 years ago