Answer:
73.5 kJ
Step-by-step explanation:
Mass of butane = 185 g
Heat of vaporization for butane = 23.1 kJ/mol
Molar mass of butane = 58.12 g/mol
Number of moles of butane = 
Energy required for burning 185 g of butane = 3.18×23.1 = 73.5 kJ
∴ Energy is required to vaporize 185 g of butane at its boiling point is 73.5 kJ
It's important to understand how perfect square trinomials work.
Say we had a factored perfect square trinomial in the form (x - n)²
If we distributed that out we'd have x² + 2nx + n².
Now, take a look at our expression... x² - 10x.
Imagine that 2nx term as 10x...n =5.
In that case, we'd have to add 25 to make our perfect square trinomial
as a rule of thumb: halve the x coefficient, square it, and then add it.
Answer:
the center (h,k) is the point (-4,5) and the radius is 11
Step-by-step explanation:
Answer:
18 sqrt 2
Step-by-step explanation:
Answer is B
Answer:
I believe it is 3?
Step-by-step explanation:
