Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
Polymomial with 4 terms i believe
Answer:
the answer is D
Step-by-step explanation:
hope this helps
Answer:
No similarity and no scale factor (I could be wrong)
Step-by-step explanation:
Don't worry, no links :)
You would see if they are similar if they have similar sides. so if there is an equal ratio, to both, they are similar. Sometimes they may not look similar until you rotate them. So for the following, you can see that if E were on the bottom, it would look like the triangle with N and M on the bottom you can ensure this to look at the ratios of each side. To find the scale factor, it depends on which way you are going. are you going from GEF to MNL or MNL to GEF? To me, it doesn't look like there is a scale factor, but I could be wrong.
Answer:
20%
Step-by-step explanation:
The percentage change can be found from ...
% change = ((new value)/(reference value) -1) × 100%
= (240/200 -1) × 100%
= 0.20 × 100%
= 20%
240 is an increase of 20% from 200.
