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Deffense [45]
3 years ago
15

A rectangle has a height of w^2+3w+9 and a width of w^2+2 express the area of the entire rectangle

Mathematics
2 answers:
lara31 [8.8K]3 years ago
6 0

Answer:

w⁴ + 3w³ + 11w² + 6w + 18

Step-by-step explanation:

Rectanle area = height * width

area = (w²+3w+9)(w² + 2)

        = w²*w² + w²*2 + 3w*w² + 3w*2 + 9*w² + 9*2

        = w⁴ + 2w² + 3w³ + 6w + 9w² + 18

        = w⁴+ 3w³ + (9w²+2w²) + 6w + 18

        = w⁴ + 3w³ + 11w² + 6w + 18

NISA [10]3 years ago
4 0

Answer:

w^4 + 3w^3 + 11w^2 + 6w + 18.

Step-by-step explanation:

Area = height * width

= (w^2 + 2)(w^2 + 3w + 9)

= w^2(w^2 + 3w + 9) + 2(w^2 + 3w + 9)

= w^4 + 3w^3 + 9w^2 + 2w^2 + 6w + 18

= w^4 + 3w^3 + 11w^2 + 6w + 18.

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F(x)=12x2-4x-8. G(x)=11x-6
AlekseyPX

Answer: Second option.

Step-by-step explanation:

Given the functions f(x) and g(x):

f(x)=12x^2-4x-8\\\\g(x)=11x-6

You need to divide them in order to find (\frac{f}{g})(x) asked in the exercise. Then:

(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}

Now, it is important to remember that, by definition, the division by zero is not defined. Therefore, the denominator of the function cannot be zero.

Let's find the value of "x" for which the denominator of the function would be zero:

1. You need to make the denominator equal to zero:

11x-6=0

2. Finally, you must solve for "x":

11x=6\\\\x=\frac{6}{11}

Therefore, as you can see, the answer is:

 (\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}, x=\frac{6}{11}

4 0
3 years ago
85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance  (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
3 years ago
Which expression represents the inverse of the function f(x)=4x
Anton [14]

Answer:

f^{-1}(x) = \frac{x}{4\\}

Step-by-step explanation:

Let y = f(x) and rearrange making x the subject

y = 4x ( divide both sides by 4 )

x = \frac{y}{4}

Change y back into terms of x

f^{-1} (x) = \frac{x}{4\\}

4 0
3 years ago
At 4:00 am, the outside temperature was -28*F. By 4:00 P.M. it rose 38 degrees. What was the temperature at 4:00 P.M. ?
andreyandreev [35.5K]
The answer would be 10 degrees
i hope this helps
7 0
3 years ago
What is the range of g(x)?
Mila [183]

Answer:

2

Step-by-step explanation:

I just need for the points

5 0
2 years ago
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