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Flura [38]
3 years ago
14

What is the range of g(x)?

Mathematics
1 answer:
Mila [183]3 years ago
5 0

Answer:

2

Step-by-step explanation:

I just need for the points

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Write each ratio 3 different ways
Alenkasestr [34]

Answer:

I don't know the number of the ratio but i will create an example of 3 ways to write ratio

Let's use the number 10:8

you can write it like

  • 10:8 (colon)
  • 10 to 8
  • 10/8 ( a fraction)
7 0
3 years ago
Select the correct answer from the drop-down menu.
Licemer1 [7]

Answer:

i think is 3/2. im no really sure

6 0
3 years ago
Write in y=mb+b form
kotykmax [81]

Answer:

y=5x+4

Step-by-step explanation:

5 is the rate of change and 4 is where the line intersects y

6 0
3 years ago
Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)
Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = \frac{1}{2}(AD+BC)

By using expression for the length of a segment between two points,

Length of a segment = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between two points A(-5, -6) and D(3, 2),

AD = \sqrt{(3+5)^2+(2+6)^2}

AD = \sqrt{64+64}

AD = \sqrt{128}

AD = 8\sqrt{2}

Distance between B(-6, -2) and C(-4, 0)

BC = \sqrt{(-6+4)^2+(-2-0)^2}

BC = \sqrt{8}

BC = 2\sqrt{2}

Therefore, m(YZ) = \frac{1}{2}(8\sqrt{2}+2\sqrt{2})

                             = \frac{1}{2} (10\sqrt{2})

                             = 5\sqrt{2}

Option C will be the answer.

7 0
3 years ago
Steve prepreformed the chemistry experiment in which divided 5/8 of a box of baking soda evenly among the five bottles he then a
weeeeeb [17]

Answer:

\mathbf{ \dfrac{1}{8} \ box}

Step-by-step explanation:

Given that:

Steve divided 5/8 of a box evenly among 5 bottles. To determine the amount of baking soda added;

Then, mathematically:

=\dfrac{5}{8} \ box \div 5

= \dfrac{5}{8} \ box \times  \dfrac{1}{5}

\mathbf{= \dfrac{1}{8} \ box}

3 0
3 years ago
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