A. ASA similarity theorem
B. SSS similarity theorem
Answer and Step-by-step explanation:
a) H o : there is no relation between job pressure and age
H 1: there is a relation between job pressure and age
b) See file attached.
c) Test statistic: For the given categorical data, we apply the x² — test Test statistic is 2.19
d) The test statistic value x² = 2.19 < 16.81, we accept the null hypothesis. Therefore, we conclude that there is no relationship between job pressure and age.
To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.
Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.
Combining the three, we have the overall GCF = 3m2n
Answer:
f(x)=5x^3-2x^2-90x-36=0
=x^2(5x-2)-18(5x-2)=(x^2-18)(5x-2)=0
x^2-18=0/5x-2=0
x^2=18=x=9√2
5x-2=0
x=2/5
zeros are 9√2,2/5
