The volume of a cylinder is written as V = πr²h. The volume is 324π cm³ and the height is 9 cm. Evaluating it, we will arrive at the value of radius as 6 cm. Area of the base can be obtained using the formula A = πr². If r = 6cm, area of the base will be 36π cm
Answer:
A) There are no Counts
B) I'll count the number of each type of nut.
Step-by-step explanation:
A) Yes, the Chi-square is not an appropriate method because the question gave us the weight of the nuts in grams and these are not counts. Whereas, the chi-square goodness-of-fit test requires that the data values are counts.
B) What i will do instead is that i will count the number of each type of nut and assume that the given percentages are also relevant for each type of nut.
Check the picture. There are 2 interior common tangents, and 2 exterior common tangents which can be drawn.
Answer: 4
Quadratic function ( in standard form ):
y = a x² + b x + c
x = 0:
635 = 0 + 0 + c
c = 635
x = 1:
644 = a + b + 635
a + b = 9
x = 2:
719 = 4 a + 2 b + 635
4 a + 2 b = 84
and now we have a system:
a + b = 9 / * ( - 2 )
4 a + 2 b = 84
-------------------------
- 2 a + 2 b = - 18
+
4 a + 2 b = 84
-------------------------
2 a = 66
a = 33; b = - 24;
Function is:
f ( x ) = 33 x² - 24 x + 635
f ( 8 ) = 33 * 64 - 24 * 8 + 635 = 2,112 - 192 + 635 = 2,555
Answer: The number of waterfowl on week 8 would be 2,555.
The answer is A all three angles are acute (less than 90°)
