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Alexxandr [17]
4 years ago
11

WILL GIVE BRAINLIEST! PLEASE SOLVE

Mathematics
1 answer:
Leto [7]4 years ago
7 0
19.
x=4
<AEB= 26 degrees
<BEF= 64 degrees

20.
x=10.75
<CFD= 58.5 degrees

Hope this helps.

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To find the solutions to the equation \left(x^2+5x+6\right)\left(x^2-3x-4\right)=0 you need to:

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Factor out x from (x^2+2x)

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Factor out 3 from 3x+6

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x^2+5x+6=x\left(x+2\right)+3\left(x+2\right)\\\\\mathrm{Factor\:out\:common\:term\:}x+2\\\\x^2+5x+6=\left(x+2\right)\left(x+3\right)

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Using the Zero Factor Theorem:

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