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4 years ago

WILL GIVE BRAINLIEST! PLEASE SOLVE

Mathematics

1 answer:

Leto [7]4 years ago

7 0

19.
x=4
<AEB= 26 degrees
<BEF= 64 degrees

20.
x=10.75
<CFD= 58.5 degrees

Hope this helps.

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What type of angles are <5 and <16

vovikov84 [41]

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3 years ago

A car traveling at a rate of 54 miles per hour. What is the car's rate in feet per secondHow many fect will the car travel in 2

Lena [83]

The car's speed in feets per second is 79.2, Hence, it will cover a distance of 158.4 feets in 2 seconds.

Car's speed in miles per hour = 54 miles per hour

Recall :

1 mile = 5280 feets
1 hour = 3600 seconds

Car's rate in feet per second

54 miles per hour = (54 × 5280 × 1/3600) feet per second = 79.2 feets per second.

Distance in 2 seconds :
Distance = speed × time
Distance = 79.2 × 2 = 158.4 feets

Therefore, the car will cover a distance of 158.4 feets in 2 seconds.

Learn more :brainly.com/question/23774048

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3 years ago

PLEASE HELP ASAP

Nikitich [7]

10 x 10 x 10 = $10^{3}$

4 0

3 years ago

Read 2 more answers

1: 40% of the students on a field trip love the museum. If there are 20 students on the field trip, how many love the museum?

Allisa [31]

20 students times 40% of them is 20 times 0.40, which is 8

499 divided by the sale price, 424.13

1.1765, or when rounded, 1.18%

1. 8 students

2. 1.18%

5 0

3 years ago

A fence is to be built to enclose a rectangular area of 1800 square feet. The fence along three sides is to be made of material

drek231 [11]

Answer:

length = 60 foot, width = 30 foot

Step-by-step explanation:

Area of rectangular part, A = 1800 ft²

Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.

Let the length of the rectangle is l and the width of the rectangle is W.

Area = Length x width

A = L x W

1800 = L x W ...... (1)

Total cost of fencing, C = 6 x ( L + W + L) + 18 x W

C = 6 (2L + W) + 18 W

C = 12 L + 24 W

Substitute the value of W from equation (1), $W=\frac{1800}{L}$ in equation (2)

$C=12L+24\times \frac{1800}{L}$

$C=12L+\frac{43200}{L}$

Differentiate both sides with respect to L:

$\frac{dC}{dL}=12-\frac{43200}{L^{2}}$

Put it equal to zero for maxima and minima

$12-\frac{43200}{L^{2}}=0$

L = 60 foot

and W = 30 foot

So, the costing is minimum for length = 60 foot and the width = 30 foot.

4 0

3 years ago