What is the effect on the graph of f(x)=1/x when it is transformed to g(x)=1/x+9?

For a test of upper h 0h0: pequals=0.50, the sample proportion is 0.470.47 based on a sample size of 100. use this information

otez555 [7]

The parts (a) to (c) can be completed using the equtaion y ⇔ Δ ∈ ∞, ㏒Δ ∀ x∈√a, a∈R.

8 0

3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

9 months ago

The perimeter of a rectangle is 96 yards and the length is 14 yards more than the width what are the dimensions of the rectangle

____ [38]

Answer:

17 yards and 31 yards.

Step-by-step explanation:

Since length is 14 more than width, lets call width: w and length: w+14

So perimeter is 96 so: 2w+2(w+14)=96

2w+2w+28=96 so 4w+28=96

4w=68 and finally w=17

So 17 yards and 31 yards.

6 0

1 year ago

Simplify the following monomials pls

velikii [3]

Answer:

1.) $a^4b$

2.) $p^3q^4$

3.) $2n^4$ $2n^4$

4.) $5xy^2z$

5.) $2a^3b^5$

I hope this helps:

4 0

3 years ago

Transforming quadratic graphs

rewona [7]

Answer:

f(x) = 3(x - 2)² + 4

OR

f(x) = 3x² - 12x + 16

Step-by-step explanation:

Vertex form of a parabola:

y = a(x - h)² + k

Standard form of a parabola:

y = ax² + bx + c

Let's find the vertex of this parabola.

(h, k) → (2, 4)

In order to find the a-value (vertex form), let's use another point besides the vertex on the parabola.

Using (3, 7) for (x, y), let's substitute this point and the vertex (2, 4) for (h, k) into the vertex form equation and solve for a.

7 = a[(3) - (2)]² + 4

Simplify using PEMDAS.

7 = a(1)² + 4
7 = a + 4

Subtract 4 from both sides.

a = 3

Now we have (h, k) and a of the vertex form.

y = a(x - h)² + k → y = 3(x - 2)² + 4

In order to convert from vertex to standard form, simplify the equation by FOILing.

y = 3(x - 2)² + 4

y = 3(x² - 4x + 4) + 4

Distribute 3 inside the parentheses.

y = 3x² - 12x + 12 + 4

Combine like terms.

y = 3x² - 12x + 16

Therefore, we have the answer:

<u>Vertex form:</u>

f(x) = 3(x - 2)² + 4

<u>Standard form:</u>

f(x) = 3x² - 12x + 16

8 0

3 years ago