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koban [17]
3 years ago
10

Rowan is walking in a shallow, clear bay, in still water just over her knees. When she looks down at her feet in the sand, she n

otes that they appear closer to her than usual. Normally, when she tips her head forward to look at her feet, her feet are 1.60 m from her eyes. How far away do her feet appear when they are under 0.60 m of water?
Physics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

Rowan's feet appears at a distance of 0.451 m under water

Solution:

As per the question:

Actual depth in water, d = 0.60 m

Normal distance of her feet from her eyes, D = 1.60 m

Now,

We know that refractive index of water, n_{w} = 1.33

Thus

To calculate the apparent height of her feet:

n_{w} = \frac{d}{Apparent\ Height, H_{apparent}}

H_{apparent} = \frac{d}{n_{w}} = \frac{0.60}{1.33} = 0.451\ m

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To answer this question, we should know the formula for the terminal velocity. The formula is written below:

v = √(2mg/ρAC)
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Let's determine the mass, m, to be density*volume.
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You watch a distant lady driving nails into her front porch at a regular rate of 1 stroke per second. You hear the sound of the
Igoryamba

Answer:

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