Answer
given,
mass of glider = 0.23 Kg
spring constant = k = 4.50 N/m
spring stretched to 0.130 m
The springs potential energy =


U = 0.038 J
at x = 0,the only energy will be kinetic .


v² = 0.3304
v = 0.575 m/s
displacement of the glider
using conservation of energy



x = 0.678 m
128.1-127.8= 0.3Hz
<span>129.1-128.1= 1.0Hz </span>
<span>129.1-127.8= 1.3Hz</span>
Answer:
32 C > 32 F > 32 K
Explanation:
32 F, 32 C, 32 K
Let T1 = 32 F
T2 = 32 C
T3 = 32 K
Convert all the temperatures in degree C
The relation between F and C is given by
(F - 32) / 9 = C / 100
so, (32 - 32) / 9 = C / 100
C = 0
So, T1 = 32 F = 0 C
The relation between c and K is given by
C = K - 273 = 32 - 273 = - 241
So, T3 = 32 K = - 241 C
So, T 1 = 0 C, T2 = 32 c, T3 = - 241 C
Thus, T2 > T1 > T3
32C > 32 F > 32 K