The nucleus of an atom contains a. only neutrons b protons and neutrons

D. A bargain hunter purchases a "gold" crown at a flea market. After she gets home, she hangs it from a scale and finds its weig

s2008m [1.1K]

Answer:

Wc = 7.84 weight of crown

Ww = 7.84 - 6.86 = .98 weight of water displaced

Density = 7.84 / .98 = 8 crown is 8 X that of water

Since gold has a density of 19.3 that of water the crown is certainly not 100 percent (if any) gold

4 0

2 years ago

An B flat is played on a french horn, whose frequency is 466Hz.

scoray [572]

Answer:

Period of one vibration = 0.00215 second (Approx.)

Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)

Explanation:

Given:

Frequency of wave = 466 Hz

Find:

Period of one vibration

Wavelength {Is speed of sound is 343 m/s]

Computation:

Period of one vibration = 1/F

Period of one vibration = 1 / 466

Period of one vibration = 0.00215 second (Approx.)

Wavelength = Velocity / Frequency

Wavelength {Is speed of sound is 343 m/s] = 343 / 466

Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)

3 0

3 years ago

Read 2 more answers

A block oscillating on a spring has a maximum speed of 20 cm/s. part a what will the block's maximum speed be if its total energ

yKpoI14uk [10]

It will be 4 times of original thus maximum speed would be 80cm/s

6 0

3 years ago

A parallel-plate capacitor initially has a potential difference of 400 V and is then disconnected from the charging battery. If

Damm [24]

The capacitance of a capacitor is the ratio of the stored charge to its potential difference, i.e.

C = Q/ΔV

C is the capacitance

Q is the stored charge

ΔV is the potential difference

Rearrange the equation:

ΔV = Q/C

We also know the capacitance of a parallel-plate capacitor is given by:

C = κε₀A/d

C is the capacitance

κ is the capacitor's dielectric constant

ε₀ is the electric constant

A is the area of the plates

d is the plate separation

If we substitute C:

ΔV = Qd/(κε₀A)

We assume the stored charge and the area of the plates don't change. Then if we double the plate spacing, i.e. we double the value of d, then the potential difference ΔV is also doubled.

5 0

3 years ago

The amplitude of a simple harmonic oscillator will be doubled by:a) doubling only the initial speedb) doubling the initial displ

OLEGan [10]

Answer:

When both initial speed and initial displacement is doubled then amplitude will be doubled.

Explanation:

Given that :- Amplitude of simple harmonic Oscillator is doubled.

So,

Formula of Simple harmonic oscillator is $X=A\sin\ (2\pi ft +\phi)$ ...........(1)

Where X = Position in (m,cm,km.....)

A = Amplitude in (m,cm,km.....)

F = Frequency in (Hz)

T = Time in (sec.)

Ф = Phase in (rad)

For initial displacement taking t=0 we get,

Initial displacement = $A\sin(\phi)$ .................(2)

Now taking equation (1) and differentiating it w.r.t to (t) we get

$\frac{dx}{dt} = 2\pi fA\cos\ (2\pi ft+\phi)$

$V= 2\pi fA\cos\ (2\pi ft+\phi)$

taking t=0 for initial speed then we get,

Initial speed = $2\pi fA\cos\phi$ ...............(3)

observing equation (2) & (3) that the initial displacement and initial speed depends on the Amplitude of the Oscillator.

Hence,

when both initial speed and displacement is doubled then amplitude will be doubled.

4 0

3 years ago