What is a factor that affects the outcome of an experiment?

Physics

2 answers:

Elis [28]3 years ago

6 0

The answer is D. Variable. Hope this Helps:)))

STALIN [3.7K]3 years ago

6 0

Answer: D-variable

Explanation:

A variable is the parameter over which changes can be made and observed so as to determine the outcome of the experiment. The two important variables such as dependent and independent variables and changes occurring over them can be useful in determining the outcome of the experiment.

An independent variable is the one which can be changed or manipulated by the experimenter so as to observe the impact of such change over the dependent variable. A dependent variable cannot be manipulated in the experiment instead the changes occurring in the dependent variable are because of the changes occurring in the independent variable. The observations on the dependent variable can be used for determining the outcome of the experiment.

You might be interested in

A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)

Ghella [55]

Fibers of the sweater lose electrons because electrons are leave it.

One of the ways of charging a body is by friction. Charges are transferred from one body to another when an object is rubbed against another. This is charging by friction.

A sweater has negative charges hence when the balloon is rubbed against the sweater, fibers of the sweater lose electrons because electrons are leave it.

Learn more: brainly.com/question/830809

4 0

2 years ago

A 10kg box accelerates forward at a rate of 12 m/s^2. What is the force acting on the box?

Allushta [10]

Answer:

120N

Explanation:

Newton's second law formula: F= ma

given that m = 10 kg, a = 12 m/s^2

F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N

5 0

2 years ago

An object with an initial velocity of 10 m/s accelerates at a rate of 3.5 m/s2 for 8 seconds. How far will it have traveled duri

ICE Princess25 [194]

Answer:

Distance, d = 192 meters

Explanation:

We have,

Initial velocity of an object is 10 m/s

Acceleration of the object is 3.5 m/s²

Time, t = 8 s

We need to find the distance travelled by the object during that time. Second equation of motion gives the distance travelled by the object. It is given by :

$d=ut+\dfrac{1}{2}at^2$