All categories

1 year ago

In a vacuum all electromagnetic waves have the same?

1 answer:

7 0

Electromagnetic waves do not need a material medium for its movement. They all travel at the same speed in a vacuum

What is Electromagnetic waves ?

Electromagnetic waves are those that do not require a material medium for their propagation. They are transverse waves which made up of electric and magnetic waves

In a vacuum all electromagnetic waves have the same speed. That is, all types of electromagnetic waves travel at the same speed in a vacuum which is equal to 299792458 m/s

Examples are;

radio wave

infrared

ultraviolet

x - rays

Gamma ray

visible light

microwave

Therefore, in a vacuum, all electromagnetic waves have the same speed.

Learn more about Waves here: brainly.com/question/25699025

#SPJ1

You might be interested in

Since protons (p*) with a positive charge and neutrons (nº) without a charge are located in the

konstantin123 [22]

Answer:

A nucleus contains protons and neutrons . Protons are positively charged and neutrons are neutral . So charge of nucleus depends upon protons . Hence , neucleus is positively charged

Explanation:

3 0

4 years ago

A diver steps off a diving platform. How fast will she be moving when she

marta [7]

Answer:

C. 14.0 m/s

Explanation:

$v_0=0\\a=g=9.9.8\\h=10\\v_f=?$

$v_f^2=v_0^2+2a \Delta h\\v_f=\sqrt{v_0^2+2a \Delta h}\\v_f=\sqrt{0+2(9.8)(10)}\\v_f=\sqrt{196}\\v_f=14$

6 0

3 years ago

An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.70 m

dimulka [17.4K]

Answer:

Explanation:

The fish will have horizontal velocity of 2.6 m/s which is also the velocity of eagle. Additionally , he will have vertical velocity due to fall under gravity .

v² = u² + 2 g H .

v² = 0 + 2 x 9.8 x 4.7 m

= 92.12

v = 9.6 m /s

The fish's final velocity will have two components

vertical component = 9.6 m/s downwards

Horizontal component = 2.6 m /s .

Resultant velocity = √ ( 9.6² + 2.6² )

= √ ( 92.16 + 6.76 )

= 9.9 m /s

3 0

3 years ago

Read 2 more answers

49W

Nikolay [14]

Answer:

Explanation:

The magnitude of the electrostatic force between two charged particles is given by

$F=\frac{kq_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the charges of the two particles

r is the separation between the particles

In this problem, the initial force between the particles is F.

Later, the distance between the two particles is increased by four, so

r' = 4r

So, the new force between the particles will be

$F'=\frac{kq_1 q_2}{(4r)^2}=\frac{kq_1 q_2}{16r^2}=\frac{1}{16}F$

So, the new force decreases by a factor of 16.

4 0

3 years ago

Do any of the atom diagrams below represent atoms of the same element?

sergeinik [125]

Atom A and atom C are the same element.

6 0

3 years ago