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zloy xaker [14]
3 years ago
9

What is 5.2x10^2 x 1.2 x 10^4

Mathematics
2 answers:
Oxana [17]3 years ago
7 0
6.24x10^6 ( the first one)
AnnZ [28]3 years ago
7 0
I got 56,070,144 if that helps at all.
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Please help ?????????
Murrr4er [49]

Answer:

B is your answer to this problem

Step-by-step explanation:

4 0
3 years ago
Please help and show working (please)
Alexxandr [17]

In mathematical notation, ∑ means summation. So wherever you see the symbol, you have to sum over all elements in the set. Let's solve the question.

a. ∑m means, to sum all elements in the set m: ∑m = 12 + 15 + 20 + 30 = 77

b. ∑f^{2} means to sum all elements in the set f as the square of the elements f = 5^{2} + 9^{2} + 10^{2} + 16^{2} = 25 + 81 + 100 + 256 = 462

c. ∑mf means to sum all elements as the product of the elements of m and f = (12×5) + (15×9) + (20(12^{2}(5)) + (15^{2}(9)) + (20^{2}(10)) + (30^{2}(16)) = 2114510) + (30×16) = 875

d. ∑m^{2}f means to sum all elements as the product of the square of m and f = ((12*12)(5)) + ((15*15)(9)) + ((20*20)(10)) + ((30*30)(16)) = 21145

4 0
3 years ago
Find the product. (4/5)(9/5)(-1/2)
MatroZZZ [7]
I believe it’s -0.72
5 0
3 years ago
Read 2 more answers
O DATA ANALYSIS AND STATISTICS Outcomes and event probability A number cube is rolled three times. An outcome is represented by
Simora [160]

ANSWER

EXPLANATION

For each of the three events, there are 8 possible outcomes, so the probability of each event is,

P(event)=\frac{favorable\text{ }outcomes}{possible\text{ }outcomes}=\frac{favorable\text{ }outcomes}{8}

• Event A:, there must be only odd numbers in the last two rolls, which are either ,EOO or OOO,. This event has 2 favorable outcomes, ,so its probability is 1/4,.

,

• Event B,: this is the complementary event to event A. Here the last two rolls must be even numbers - both or only one of the last two: ,OOE, EEO, EOE, OEE, EEE, OEO,. This event has 6 favorable outcomes, so ,its probability is 3/4,.

,

• Event C,: this event is when the first and last rolls are even numbers in the same event. This is either ,EOE or EEE,. Since this event has 2 favorable outcomes, ,its probability is 1/4,.

5 0
1 year ago
A Ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the Ferris wheel makes one comp
Morgarella [4.7K]

Answer:

y = 11 - 10cos(0.1\pi t)

Step-by-step explanation:

Suppose at t = 0 the person is 1m above the ground and going up

Knowing that the wheel completes 1 revolution every 20s and 1 revolution = 2π rad in angle, we can calculate the angular speed

2π / 20 = 0.1π rad/s

The height above ground would be the sum of the vertical distance from the ground to the bottom of the wheel and the vertical distance from the bottom of the wheel to the person, which is the wheel radius subtracted by the vertical distance of the person to the center of the wheel.

y = h_g + d_b = h_g + R - d_c (1)

where h_g = 1 is vertical distance from the ground to the bottom of the wheel, d_b is the vertical distance from the bottom of the wheel to the person, R = 10 is the wheel radius, d_c is the vertical distance of the person to the center of the wheel.

So solve for d_c in term of t, we just need to find the cosine of angle θ it has swept after time t and multiply it with R

d_c = Rcos(\theta(t)) = Rcos(\omega t) = 10cos(0.1\pi t)

Note that d_c is negative when angle θ gets between π/2 (90 degrees) and 3π/2 (270 degrees) but that is expected since it would mean adding the vertical distance to the wheel radius.

Therefore, if we plug this into equation (1) then

y = h_g + R - d_c = 1 + 10 - 10cos(0.1\pi t) = 11 - 10cos(0.1\pi t)

7 0
3 years ago
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