Answer:
ABC is an isosceles triangle.
Because it consists of two congruent triangles created by CD, side AC = CB, making it an isosceles triangle.
Step-by-step explanation:
I can conclude that triangle ABC is an isosceles triangle.
Perpendicular means intersecting at 90°. Bisector means intersecting at the midpoint, halfway between the two ends.
Since CD is dropped from vertex C and is a perpendicular bisector of AB, angle C is also bisected.
Therefore angle C for both triangles CDA and CDB is of equal measure.
We know angle D for both triangle CDA and CDB is of equal measure, 90°, because CD is a <em>perpendicular </em>bisector of AB.
The two triangles also share the same side CD.
Triangles CDA and CDB are congruent for having 2 equal angles and 1 equal side (ASA property).
Since they are congruent, AD = AB and AC = CB. Therefore triangle ABC is an isosceles triangle.
Rewrite it in the form a^2 - b^2, where a = 7q^2 and b = 2
(7q^2)^2 - 2^2
Use the Difference of Squares; a^2 - b^2 = (a + b)(a - b)
<u>= (7q^2 + 2)(7q^2 - 2)</u>
I would think that thwe equation used to solve it would be 0.2 - r = s.