The sum of two consecutive integers is 81. Determine the lesser of the two numbers.
1 answer:
Given that,
the two numbers are consecutive
The two numbers are
x and x + 1
Sum of the numbers = 81
x + (x + 1) = 81
x + x + 1 = 81
2x = 81 - 1
2x = 80
x = 80/2
x = 40
Therefore, <em>the two numbers are</em> x = 40 and x + 1 = 41
You might be interested in
The answer is definately A
Answer:
5
Step-by-step explanation:
Idk you kno I am trying to get points right
Answer:
-10
Step-by-step explanation:
so,a=-10
Total money in account=125+25n
