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V125BC [204]
3 years ago
11

HEY!! I’M REALLY DESPERATE RN FOR AN ANSWER SO LIKE HERE’S ALL MY POINTS!! Please show the work!

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

One way to divide is to use the divisor as a factor in the numerator

Consider the numerator

x²(x - 3) + 3x² - x + 6

= x²(x - 3) + 3x(x - 3) + 9x - x + 6

= x²(x - 3) + 3x(x - 3) + 8(x - 3) + 24 + 6

= x²(x - 3) + 3x(x - 3) + 8(x - 3) + 30

quotient = x² + 3x + 8 , remainder = 30

\frac{x^3-x+6}{x-3} = x² + 3x + 8 + \frac{30}{x-3}

7nadin3 [17]3 years ago
6 0

Answer:

what does the mbw stand for

Step-by-step explanation:

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6 0
3 years ago
What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
3 years ago
Help me please, not very good at math. Thank u:)
ozzi

Answer:

76cm^2

Step-by-step explanation:

Separate the shape into two different rectangles. Then add the area of the rectangles together.

4 x 4 = 16

6 x 10 = 60

16 + 60 = 76

8 0
2 years ago
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3 years ago
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Given directed line segment PR, find the coordinates of Q on PR such that the ratio of PQ to QR is 2:1.
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Answer:

4/3, -3

Step-by-step explanation:

4 0
3 years ago
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