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12345 [234]
3 years ago
7

Probability and statistics help!

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

It’s 2 and 8 as the left end of the box is Q1 and the right end of the box is Q3. I’m a little rusty on box and whisper plots but this should be correct.

You might be interested in
Find the midpoint of (-5,12) and (3,-6)
exis [7]

Answer:

mid point: (4,5)

hope that helps :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors
mezya [45]
<h3>Answer:  491,891,400</h3>

Delete the commas if necessary.

============================================================

Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

  • 15 ways to pick the freshmen
  • 1287 ways to pick the sophomores
  • 70 ways to pick the juniors
  • 364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0
2 years ago
Please help with math
notka56 [123]

Choice C

(0,-2) is a point

put 0 into each equation and see if it gives you -2

A, c, d will give you -2

(2,0)

Only C gives you 0

5 0
3 years ago
Can you use the Pythagorean theorem to relate thethree sides of this triangle?
irina1246 [14]

Answer:

You can use the Pythagorean Theorem to find the length of the hypotenuse of a right triangle if you know the length of the triangle's other two sides, called the legs. You can use the Pythagorean Theorem to find a value for the length of c, the hypotenuse.

6 0
3 years ago
Answer this as soon as possible
kenny6666 [7]

Answer:

21+3t

If really want equation answer it would be -7 but it simplifying. :)

Step-by-step explanation:

6(4+t)-3(t+1)

Simplify parenthesis first.

24+6t-3t-3

Simplify like terms

24-3+6t-3t

21+3t

5 0
3 years ago
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