In the figure, AB∥CD. Find x and y.
2 answers:
Answer:
y=131°
x=53°
Step-by-step explanation:
∠ ABD and ∠ BDC are supplementary.
The sum of the supplementary angles =180 °
thus y-4+x=180...........i
x and 37° are complementary, that is, they add up to 90°
Thus, x=90-37=53°
Using this value in equation 1 we obtain:
y-4°+53° =180°
y= 180°-53°+4°
y=131°
Answer:
x = 53°
y = 131°
Step-by-step explanation:
From the figure we can see a right angled triangle.
AB∥CD
<u>To find the value of x and y</u>
Consider the large triangle, by using angle sum property we can write,
90 + 37 + x = 180
127 + x = 180
x = 180 - 127
x = 53°
Since AB∥CD and BD is a traversal on these parallel lines.
Therefore <ABD and < CDB are supplementary
we have x = 53°,
x + (y - 4) = 180
53 + y - 4 = 180
y = 180 - 49 = 131°
y = 131°
You might be interested in
10 ft and 2 because I did the math
80 lbs of material.
Hope this helps!!
~Kiwi
4.024
Four and twenty four hundredths
G^5 -g = g(g^4 -1)=g(g^2 -1)(g^2 +1) = g(g-1)(g+1)(g^2 +1)
24g^2 -6g^4 = 6g^2(4 -g^2) = 6g^2(2 -g)(2 +g)