Find the 9th and pth terms of the A.p. 2, 5 , 8..
1 answer:
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Answer:
20.
22.
24.
Step-by-step explanation:
20.
The GCF is x, so you group it out of the equation first.
Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.
The two numbers would be -6 and 8. You then differentiate the squares.
22.
The GCF is 2, so you must group it out.
Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.
The two numbers would be 1 and 4. Finally, differentiate the squares.
24.
The GCF is 5m, so you must group it out.
Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.
The two numbers would be -1 and 7. Finally, differentiate the squares.
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .