1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nexus9112 [7]
3 years ago
15

A teacher can spend as much as $125.00 to take students to a movie, a movie theater charges a $10.00 group fee and $5.50 per tic

ket.
Which of the following inequalities represents the problem and could be solved to find the maximum number of students, 2, who could attend the movie?

A 10 + 5.52 > 125
B 10 +5.5% < 125
C (10 +5.5.c) < 125
D 5.5 + 10% < 125
Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Irina-Kira [14]3 years ago
3 0
The answer is C, as it is the only one that makes sense
You might be interested in
What is the answer to 9(5x)
ser-zykov [4K]

Answer:

45x

Step-by-step explanation:

9(5x)

9 * 5 = 45

45x

7 0
3 years ago
4. What is the value of |-3.8/? *<br> Your answer<br> This is a required question
Marrrta [24]

Answer:

3.8

Step-by-step explanation:

the absolute value of any negative number is going to be positive.

6 0
4 years ago
Please help meee and show all steps please!!!ty
kolbaska11 [484]

Answer:

x = -4 and x = 5

Step-by-step explanation:

Since x^2 + 2x and 3x + 20 both equal to y, we know that the expressions equal to each other. We can write a new equation base on that.

x^2 + 2x = 3x + 20

Now we solve the equation.

x^2 + 2x = 3x + 20

x^2 - x = 20

x^2 - x - 20 = 0

(x + 4) (x - 5) = 0

x + 4 = 0 ; x -5 = 0

x = -4 ; x = 5

3 0
3 years ago
I need an explanation for this please
jeka57 [31]

Answer:

I cant

Step-by-step explanation:

Im sorry

8 0
3 years ago
At an interest rate of 8% compounded annually, how long will it take to double the following investments?
Paladinen [302]
Let's see, if the first one has a Principal of $50, when it doubles the accumulated amount will then be $100,

recall your logarithm rules for an exponential,

\bf \textit{Logarithm of exponentials}\\\\&#10;log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\&#10;-------------------------------\\\\&#10;\qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;

\bf A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$100\\&#10;P=\textit{original amount deposited}\to &\$50\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annnually, thus once}&#10;\end{array}\to &1\\&#10;t=years&#10;\end{cases}&#10;\\\\\\&#10;100=50\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 100=50(1.08)^t&#10;\\\\\\&#10;\cfrac{100}{50}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)&#10;\\\\\\&#10;

\bf log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\&#10;-------------------------------\\\\&#10;

now, for the second amount, if the Principal is 500, the accumulated amount is 1000 when doubled,

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$1000\\&#10;P=\textit{original amount deposited}\to &\$500\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annnually, thus once}&#10;\end{array}\to &1\\&#10;t=years&#10;\end{cases}&#10;\\\\\\&#10;1000=500\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 1000=500(1.08)^t&#10;\\\\\\&#10;

\bf \cfrac{1000}{500}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)&#10;\\\\\\&#10;log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\&#10;-------------------------------

now, for the last, Principal is 1700, amount is then 3400,

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$3400\\&#10;P=\textit{original amount deposited}\to &\$1700\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annnually, thus once}&#10;\end{array}\to &1\\&#10;t=years&#10;\end{cases}

\bf 3400=1700\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 3400=1700(1.08)^t&#10;\\\\\\&#10;\cfrac{3400}{1700}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)&#10;\\\\\\&#10;log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t
8 0
4 years ago
Other questions:
  • Express 40 % as a simplified ratio
    12·2 answers
  • A angle addition postulate
    13·1 answer
  • Pls help me with this answer choice question! brainliest, rattings, thanks etc.
    7·1 answer
  • Kendra is twice as old as Tim. In 10 years, Kendra will be four years older than Tim. How old are Kendra and Tim now?​
    5·1 answer
  • The sum of the angle measures of a polygon with n sides is 540. Find n.<br> no
    15·1 answer
  • Dalton is playing a game in which the object is to obtain a 0 by adding the points scored during each round
    6·1 answer
  • Find Ms. Buggie's mistake in the following problem. Then, give what the correct answer should be.
    8·1 answer
  • How do you find your y-intercept from your x-y points?
    11·1 answer
  • Plssssssssssssssssssssssss help
    10·2 answers
  • 3 metres of material cost £1.56<br> Work out the cost of 5 metres of the same material.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!