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zzz [600]
3 years ago
10

You can go back to the previous or next location on the window using the

Computers and Technology
1 answer:
fenix001 [56]3 years ago
3 0
Alt key and pressing the left or right arrow
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Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
3 years ago
The while loop and the do loop are equivalent in their expressive power; in other words, you can rewrite a while loop using a do
sleet_krkn [62]
I think False...

I hope this helps
8 0
3 years ago
Write the definition of a method printDottedLine, which has no parameters and doesn't return anything. The method prints to stan
Bond [772]

Answer:

public static void printDottedLine()

{

  System.out.println(".....");

}

Explanation:

The above written code is in JAVA and it is the method definition of the method mentioned in the question.Since the method returns nothing hence it's return type is void and it does not have any arguments hence there is nothing written in the parenthesis.In JAVA System.out.println is used for standard output and trminates them by newline.

3 0
3 years ago
What three files do you need to perform a mail merge?<br><br> HELP ASAP PLEASE!!
Burka [1]

The 3 files you need to have for a successful mail merge are:

  • An Excel spreadsheet works
  • Outlook Contact List.
  • Apple Contacts List or Text file, etc.

<h3>What is Mail Merge?</h3>

This is known to be the act of carrying out  a Mail Merge and it is one where a person will need to use a Word document and a recipient list, that is an Excel workbook.

Files needed are:

  • Text file,
  • address files, etc.

The 3 files you need to have for a successful mail merge are:

An Excel spreadsheet worksOutlook Contact List.

Apple Contacts List or Text file, etc.

Learn more about mail merge from

brainly.com/question/20904639

#SPJ1

4 0
2 years ago
Write a program using integers userNum and x as input, and output userNum divided by x four times. Ex: If the input is: 2000 2
STatiana [176]

Answer:

// here is code in c++.

// include header

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables to read input

   int userNum,x;

   cout<<"enter the value of userNum and x :";

   // read the input from user

   cin>>userNum>>x;

   // divide the userNum with x 4 times

   for(int a=0;a<4;a++)

   {

       userNum=userNum/x;

       cout<<userNum<<" ";

   }

       cout<<endl;

return 0;

}

Explanation:

Declare two variables "userNum" and "x". Read the value of these. Run a for loop 4 time and divide the "userNum" with "x" and print  the value of "userNum".

<u>Output:</u>

enter the value of userNum and x :2000 2                                                                                  

1000 500 250 125  

3 0
3 years ago
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