All categories

3 years ago

What kind of substances can you not heat on a Bunsen burner?

Chemistry

1 answer:

nydimaria [60]3 years ago

3 0

Answer:

Substances which are non heat-resistant and volatile organic liquid with flammable vapor.

Explanation:

Bunsen Burner are used as a source of fire in the laboratory for heating up substances. Extra care however should be taken during heating in order to prevent fire or other forms of accidents.

Heating of mind heat resistant substances should be frowned at as the substances may get heated up and melt thereby exposing the liquid substances which may be flammable to fire thereby causing fire outbreak.

Heating of volatile organic liquid with flammable vapor should also be discouraged to prevent fire accidents.

You might be interested in

A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the

Sedbober [7]

<u>Answer:</u> The final temperature will be $52.74^oC$

<u>Explanation:</u>

Calculating the heat released or absorbed for the process:

$q=m\times C\times (T_2-T_1)$

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

$q_1=-q_2$

$m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2)$ ......(1)

where,

C = heat capacity of water = $4.184J/g^oC$

$m_1$ = mass of water of sample 1 = 100.0 g

$m_2$ = mass of water of sample 2 = 71.0 g

$T_f$ = final temperature of the system = ?

$T_1$ = initial temperature of water of sample 1 = $27^oC$

$T_2$ = initial temperature of the water of sample 2 = $89.0^oC$

Putting values in equation 1, we get:

$100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC$

Hence, the final temperature will be $52.74^oC$

6 0

3 years ago

Q401YzNjg1/details

Sholpan [36]

Answer:

siof4 su8f adfi5 9id7 mdsyfn8 dsjfd8ie3 4yb4uj 4bnu4b 4uj4k 38h1487y76 bis4can d2f9id fvs98nd

Explanation:us8s f7 ds8a das8 jf7sd 87sd 45s67f8

8 0

3 years ago

Which of the following pure compounds will exhibit hydrogen bonding?

Stolb23 [73]

Answer:

A, F, H

Explanation:

Hydrogen bonding occurs between compounds that make N-H, O-H, and F-H bonds. Just because a compound has a N, O, and F atom in the molecule doesn't mean that the compound will exhibit hydrogen bonding. The N, O, or F must be bonded to a hydrogen. Carbon-hydrogen bonds do not cause hydrogen bonding.

This means that A, F, and H will have hydrogen bonding.

4 0

3 years ago

Read 2 more answers

QUESTION 2

Aleksandr [31]

Answer:

you can see the answer at the pic

4 0

3 years ago

Moseley made revisions to the periodic table that resolved some of the problems with Mendeleev’s version. Which of these was a r

sveticcg [70]

Thanks to Moseley's revision, the importance of the atomic number was acknowledged and it explained why some elements seemed to be out of their place, even though they were actually not.

3 0

3 years ago

Read 2 more answers