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Brut [27]
3 years ago
15

QUESTION 2

Chemistry
1 answer:
Aleksandr [31]3 years ago
4 0

Answer:

you can see the answer at the pic

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Which of the following statements is true about what happens in all chemical reactions? A. The ways in which atoms are joined to
antoniya [11.8K]

Answer:

B.bonds are broken and new bonds are formed

4 0
3 years ago
Calculate the number of moles in 7g of nitrogen gas​
Andru [333]

Answer:

<h3>0.2498molN_{2}</h3>

Explanation:

7gN2 x \frac{1 mol}{2(14.01) g}

=0.2498mol N2

Nitrogen gas has the formula N_{2} so therefore that means you would have to multiply the mass in the molar by 2. To solve for the number of moles you need to cancel out the grams, you do this by using the molar mass of nitrgoen gas. You get the value on in the denominator from the periodic table (atomic mass of element). The grams will cancel out, leaving you with the number of moles when you divide 7/2(14.01).

5 0
3 years ago
PLEASE HELP: You have been given 0.507 moles of cesium fluoride (CsF), determine the mass in grams of cesium fluoride that you h
Degger [83]

Answer:

C because 77.0 CsF

Explanation:

That is the correct answer because I have that homework and i got it right

5 0
2 years ago
14.7 grams of magnesium reacts completely with 9.7 grams of oxygen to form magnesium oxide (MgO). What is the percent compositio
swat32
The answer is 60.3% magnesium, 39.7% oxygen.
Solution:
The chemical equation for the reaction is 2 Mg + O2 → 2 MgO.
Since magnesium reacts completely with oxygen, it is the limiting reactant in the reaction. Hence, we can use the number of moles of magnesium to get the mass of MgO produced:
     moles of magnesium = 14.7g / 24.305g mol-1
                                       = 0.6048 mol

     mass of MgO = 0.6048mol Mg(2 mol MgO/2mol Mg)(40.3044g MgO/1 mol MgO) 
                           = 24.376g MgO

We can now solve for the percentage of magnesium:
     % Mg = (14.7g Mg / 24.376g MgO)*100% = 60.3%

We also use the number of moles of magnesium to get the mass of oxygen consumed in the reaction:
     mass of O2 =  0.6048 mol Mg (1mol O2 / 2mol Mg) (31.998g / 1mol O2) 
                        = 9.676g

The percentage of oxygen is therefore
     % O2 = (9.676g O2 / 24.376g MgO)*100%
               = 39.7%
Notice that we can just subtract the magnesium's percentage from 100% to get 
     % O2 = 100% - 60.3% = 39.7%
5 0
3 years ago
What is the mass, in grams, of one mole of any substance known as?
lbvjy [14]
It is known as its molar mass.
5 0
3 years ago
Read 2 more answers
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