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3 years ago

15

The equation r=3c +5 represents the values shown in the table below C- 6, 8, 12, 18 R- 23, 29, ?, 59 What is the missing value i

n the table?

2 answers:

Kipish [7]3 years ago

4 0

C: 41 is the missing value in the table

almond37 [142]3 years ago

3 0

The missing value is 53.

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Why is the answer to life according to Math 42?

lapo4ka [179]

Answer:

Because Douglas Adams said that it was the answer to life, the galaxy, the universe and everything in the Hitchhiker's Guide to the Galaxy, and it was just a joke, but now people are obsessed over it.

Step-by-step explanation:

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2 years ago

August hosted two dinner parties for his friends. Twenty guests attended the first party, and twenty-eight guests attended the s

Neporo4naja [7]

25+25x=27
<span>25x=2 </span>
<span>x=2/25 </span>
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<span>8%</span>

8 0

2 years ago

Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$

Substitute:

$\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}$

Combine fractions:

$\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}$

Simplify:

$6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}$

Q.E.D.

6 0

2 years ago

2. Write the equation of the line that passes

jenyasd209 [6]

Answer:

y = x + 1 which is marked by the broken line

6 0

2 years ago

Change the line 3x − 8y = 5 into slope-intercept form.

Nimfa-mama [501]

Slope is y=mx+b
m=slope
b=y intercept

solve for y basically

3x-8y=5
minus 3x both sides
-8y=-3x+5
divide both sides by -8
$y=\frac{3}{8}x-\frac{5}{8}$

4 0

2 years ago