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mario62 [17]
3 years ago
12

The value of a stock increases at a rate of 1/2% per year. If the initial value of the stock $40 a share, when will the value of

the stock be $50? Round your answer to the nearest tenth of a year
Mathematics
2 answers:
natka813 [3]3 years ago
4 0

Answer:

After 50 years the stock value will be $50 per share.

Step-by-step explanation:

Simple Interest Equation (Principal + Interest)

A = P(1 + rt)

Where:

A = Future amont = $50

P = Principal Amount = $40

r = Rate of Interest per year in decimal; r = R/100 = 0.5/100 = 0.005

t = Time Period involved in months or years  

Plug in the values

50 = 40(1 + 0.005t)

50 / 40 = (1 + 0.005t)

5/4 = 1 + 0.005t

5/4 - 1 = 0.005t

0.25 = 0.005t

t = 0.25 / 0.005

t = 50 years

vagabundo [1.1K]3 years ago
3 0

Answer:

44. 7 yr

Step-by-step explanation:

The compound interest equation is

A = P(1+ \frac{r }{ n})^{nt}

You don't give the frequency of compounding, so I will assume that it is once per year.

Data:

P = $40

r = 0.5 % = 0.005

n =1  

Calculations:

(a) Calculate A

A = P + I = 40 + 10 = $50

(b) Calculate t

50 = 40(1+ \frac{0.005 }{ 1})^{1 \times t}\\50 = 40(1+ 0.005)^{t}

Divide each side by 40

1.25 = 1.005^{t}

Take the logarithm of each side

 log1.25 = tlog1.005

0.09691 = 0.002 166t

Divide each side by 0.002 166

t = 44.7 yr

The value of the stock will be $50 in 44.7 yr.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given data

payment (P) = $100

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rate of interest ( r ) = 1.5 %  i.e. = 0.015

time period (t) = 45 years

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future payment and interest after 45 year

solution

we know future payment formula i.e. given below

future payment = payment × (1+\frac{r}{n})^{nt} - 1) / (r/n)

now put all these value in equation

future payment = $ 100  × (1+\frac{0.015}{12})^{12*45} - 1) / (0.015/12)  

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total interest = future payment  - money paid

total interest = $77056.42 - $54000

total interest = $23056.42

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