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Vikki [24]
3 years ago
14

Need help asap pls !

Mathematics
1 answer:
matrenka [14]3 years ago
8 0

Answer:

L={∅}

Step-by-step explanation:

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Which of the events below is an example of a conditional probability?
igomit [66]
Statement 1 is an example of conditional probability.

Events with conditional probability always follow the format:

The probability of A happening, given that B has already happened.
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What is the product of 45,693*532?write you answer in words​
AlekseyPX
24,308,676
Twenty-four million three hundred eight thousand six hundred seventy-six
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Find all solutions in the interval [0, 2π). <br> 2 sin2x = sin x
tester [92]

Answer:

The solutions on the given interval are :

0

\pi

\cos^{-1}(\frac{1}{4})

-\cos^{-1}(\frac{1}{4})+2\pi

Step-by-step explanation:

We will need the double angle identity \sin(2x)=2\sin(x)\cos(x).

Let's begin:

2\sin(2x)=\sin(x)

Use double angle identity mentioned on left hand side:

2\cdot 2\sin(x)\cos(x)=\sin(x)

Simplify a little bit on left side:

4\sin(x)\cos(x)=\sin(x)

Subtract \sin(x) on both sides:

4\sin(x)\cos(x)-\sin(x)=0

Factor left hand side:

\sin(x)[4\cos(x)-1]=0

Set both factors equal to 0 because at least of them has to be 0 in order for the equation to be true:

\sin(x)=0 \text{ or } 4\cos(x)-1=0

The first is easy what angles \theta are y-coordinates on the unit circle 0. That happens at 0 and \pi on the given range of x (this x is not be confused with the x-coordinate).

Now let's look at the second equation:

4\cos(x)-1=0

Isolate \cos(x).

Add 1 on both sides:

4 \cos(x)=1

Divide both sides by 4:

\cos(x)=\frac{1}{4}

This is not as easy as finding on the unit circle.

We know \arccos( ) will render us a value between 0 and 2\pi.

So one solution on the given interval for x is x=\cos^{-1}(\frac{1}{4}).

We know cosine function is even.

So an equivalent equation is:

\cos(-x)=\frac{1}{4}

Apply \cos^{-1} to both sides:

-x=\cos^{-1}(\frac{1}{4})

Multiply both sides by -1:

x=-\cos^{-1}(\frac{1}{4})

This going to be negative in the 4th quadrant but if we wrap around the unit circle, 2\pi , we will get an answer between 0 and 2\pi.

So the solutions on the given interval are :

0

\pi

\cos^{-1}(\frac{1}{4})

-\cos^{-1}(\frac{1}{4})+2\pi

5 0
3 years ago
Please help me on this
Leokris [45]

Answer:

17 yards

I don't really have an explanation

3 0
4 years ago
Definition: An equation with a degree of 2.
NikAS [45]

Answer:

here's an equation that has a degree of 2

4x^2-37x+19

or

(x+3)(x-1)

=(x^2+2x-3)

5 0
4 years ago
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