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2 years ago

What is the standard form for 9.4/10^2

Mathematics

1 answer:

bezimeni [28]2 years ago

5 0

9x4/10x10 is the standard form for 9.4/10^2

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How many different permutations can you make with the letters in the word s e v e n t e e n ? A. 7,560 B. 17! C. 15,120 D. 3,780

Bess [88]

I'm not 100% sure if I'm doing it the right way, but I think the answer is the factorial of the number of letters divided by the factorials of the number of elements of each kind of element (in this case, the same letters)

9!/1!4!1!2!1!

= 9 · 8 · 7 · 6 · 5 · 4!/4!2!

= 9 · 8 · 7 · 6 · 5/2

= 9 · 4 · 7 · 6 · 5

= 63 · 120

= 7,560 permutations

8 0

3 years ago

Read 2 more answers

Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0

1 year ago

Or the figure shown on the right, find m∠3 and m∠4.

ioda

Answer:

m<3=84

m<4=96

Step-by-step explanation:

180-43-41=96

180-96=84

4 0

2 years ago

Read 2 more answers

A^3+a+a^2+1 2a^2+2ab+ab^2+b^3

Vikentia [17]

$\frac{a^3+a+a^2+1}{a^3+a^2+ab^2+b^2} \cdot \frac{2a^2+2ab+ab^2+b^3}{a^3+a+a^2b+b} =\frac{a(a^2+1)+1(a^2+1)}{a^2(a+1)+b^2(a+1)} \cdot \frac{2a(a+b)+b^2(a+b)}{a(a^2+1)+b(a^2+1)} =\\\\=\frac{(a^2+1)(a+1)}{(a+1)(a^2+b^2)} \cdot \frac{(a+b)(2a+b^2)}{(a^2+1)(a+b)} = \frac{2a+b^2}{a^2+b^2}$

6 0

2 years ago

The exponent indicates how many times the blank is used as a factor

Tamiku [17]

The exponent indicates how many times the number is used as a factor

7 0

3 years ago