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3 years ago

Find formula for nth term of sequence -1, 1/2, -1/3,1/4,-1/5,

Mathematics

1 answer:

Reika [66]3 years ago

6 0

I have to make twenty characters, but the answer is 1/n

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= 3x +15 <br> = 4x-10<br><br> What is the value of x?

Viefleur [7K]

Answer:

3x+15= 4x-10

3x-4x= -10-15

-x= -25(minus will be cut on both sides)

so x= 25

7 0

3 years ago

The larger leg of a right triangle is 2 feet longer than its smaller leg. The hypotenuse is 4 feet longer than the smaller leg.

maks197457 [2]

Hope it helps you:))

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3 years ago

Find the measure of m∠K

Jobisdone [24]

Answer:

<k = 20

Step-by-step explanation:

Inscribed Angle = 1/2Intercepted Arc

<K = 1/2 (40)

<k = 20

5 0

3 years ago

Question in picture above

almond37 [142]

A is the correct answer

8 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago