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Flura [38]
3 years ago
12

Find formula for nth term of sequence -1, 1/2, -1/3,1/4,-1/5,

Mathematics
1 answer:
Reika [66]3 years ago
6 0
I have to make twenty characters, but the answer is 1/n
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= 3x +15 <br> = 4x-10<br><br> What is the value of x?
Viefleur [7K]

Answer:

3x+15= 4x-10

3x-4x= -10-15

-x= -25(minus will be cut on both sides)

so x= 25

7 0
3 years ago
The larger leg of a right triangle is 2 feet longer than its smaller leg. The hypotenuse is 4 feet longer than the smaller leg.
maks197457 [2]
Hope it helps you:))

7 0
3 years ago
Find the measure of m∠K
Jobisdone [24]

Answer:

<k = 20

Step-by-step explanation:

Inscribed Angle = 1/2Intercepted Arc

<K = 1/2 (40)

<k = 20

5 0
3 years ago
Question in picture above
almond37 [142]
A is the correct answer
8 0
3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
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