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denpristay [2]
3 years ago
11

Determine whether the forces in the pair are pulling at right angles to each other.

Mathematics
1 answer:
snow_tiger [21]3 years ago
4 0
Given:
right triangle
a = 2.9
c = 4.2

Pythagorean Theorem: a² + b² = c²

missing value of b.

b² = c² - a²
b² = (4.2)² - (2.9)²
b² = 17.64 - 8.41
b² = 9.23
b = √9.23
b = 3.03 or 3.0 

The value of b is 3.0
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Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:
ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

\dfrac{\partial f}{\partial y}=6y=0\implies y=0

so the point (1, 0) is the only critical point, at which we have

f(1,0)=-7

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t

Find the critical points of <em>g</em> :

\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0

\implies\sin t=0\text{ OR }1+5\cos t=0

\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi

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t=0\implies f(10,0)=155

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t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

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4 0
3 years ago
F(x)=3x-3<br><br>g(x) 3x^3+5<br>Find F(-3) and g(-2)
astra-53 [7]

Answer:

f(-3) = -12

g(-2) = -19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 3x - 3

g(x) = 3x³ + 5

f(-3) is <em>x</em> = -3 for function f(x)

g(-2) is <em>x</em> = -2 for function g(x)

<u>Step 2: Evaluate</u>

f(-3)

  1. Substitute in <em>x</em> [Function f(x)]:                                                                           f(-3) = 3(-3) - 3
  2. Multiply:                                                                                                             f(-3) = -9 - 3
  3. Subtract:                                                                                                            f(-3) = -12

g(-2)

  1. Substitute in <em>x</em> [Function g(x)]:                                                                         g(-2) = 3(-2)³ + 5
  2. Exponents:                                                                                                        g(-2) = 3(-8) + 5
  3. Multiply:                                                                                                            g(-2) = -24 + 5
  4. Add:                                                                                                                   g(-2) = -19
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Answer:

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Step-by-step explanation:

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1.8 × sin50° = x , then

x ≈ 1.4 ( to the nearest tenth )

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