Warning: This might be rough...
First draw it out. Label the angles at the corners of the triangle 60 (definition of equilateral triangles). Now draw a line from the center of the circle to the corner, splitting the corner in half. Label this line R and a corner as 30 degrees. No to find the height of this triangle, you do rsin(30). The base of this triangle is 2rcos(30). Now find the area of this mini triangle (rsin(30)*2rcos(30)/2=r/2*rsqrt(3)/2=r^2sqrt(3)/4). Now multiply this by 3 because you have 3 mini triangles... to get...
<span>r^2 3sqrt(3)/4</span>
Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
I have no answer i just doing it for point
Answer:
x=0.59
Step-by-step explanation:
because if u divide 5.9 by 10 it will give u 0.59
and isolate x
Answer:
13/20 = 65%
Step-by-step explanation:
1/4 = 25%
7/10 = 70%
13/20 = 65%
Only the last one had the correct percentage.
