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3 years ago

6n-3>-18 Solve the inequality

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

Answer:

Step-by-step explanation:

First, you have to isolate it on one side of the equation. Remember that, isolate n on one side of the equation.

6n-3>-18

6n-3+3>-18+3 (Add 3 from both sides.)

-18+3 (Solve.)

-18+3=-15

6n>-15

6n/6>-15/6 (Divide by 6 from both sides.)

-15/6 (Solve.)

-15/6=-5/2

n>-5/2

In conclusion, the correct answer is n>-5/2.

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A color printer prints 23 pages in 9 minutes. How many pages does it print per minute? Round to the nearest hundredth. No links

never [62]

Answer:

2.56

Step-by-step explanation:

To find out how many pages the printer prints per minute, you need to divide the amount of pages it printed with how long it printed.

So 23÷9

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3 years ago

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A number x divided by -1 is at least -4. what is the inequality

Svet_ta [14]

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Step-by-step explanation:I will change my anwser when you clarify

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3 years ago

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A tank is filled with 1000 liters of pure water. Brine containing 0.04 kg of salt per liter enters the tank at 9 liters per minu

klemol [59]

Answer:

The differential equation which describes the mixing process is $\frac{dc_{salt,out}}{dt} + \frac{2}{125}\cdot c_{salt,out} = \frac{71}{100000}$ .

Step-by-step explanation:

The mixing process within the tank is modelled after the Principle of Mass Conservation, which states that:

$\dot m_{salt,in} - \dot m_{salt,out} = \frac{dm_{tank}}{dt}$

Physically speaking, mass flow of salt is equal to the product of volume flow of water and salt concentration. Then:

$\dot V_{water, in, 1}\cdot c_{salt, in,1} + \dot V_{water, in, 2} \cdot c_{salt,in, 2} - \dot V_{water, out}\cdot c_{salt, out} = V_{tank}\cdot \frac{dc_{salt,out}}{dt}$

Given that $\dot V_{water, in, 1} = 9\,\frac{L}{min}$ , $\dot V_{water, in, 2} = 7\,\frac{L}{min}$ , $c_{salt,in,1} = 0.04\,\frac{kg}{L}$ , $c_{salt, in, 2} = 0.05\,\frac{kg}{L}$ , $\dot V_{water, out} = 16\,\frac{L}{min}$ and $V_{tank} = 1000\,L$ , the differential equation that describes the system is:

$0.71 - 16\cdot c_{salt,out} = 1000\cdot \frac{dc_{salt,out}}{dt}$

$1000\cdot \frac{dc_{salt, out}}{dt} + 16\cdot c_{salt, out} = 0.71$

$\frac{dc_{salt,out}}{dt} + \frac{2}{125}\cdot c_{salt,out} = \frac{71}{100000}$

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3 years ago

For his phone service, Michael pays a monthly fee of $16, and he pays an additional $0.04 per minute if use. The least he has be

ikadub [295]

Answer: The least number of minutes that he has used his phone in a month is 1248

Step-by-step explanation:

Let m represent the number of minutes that he used his phone in a month.

For his phone service, Michael pays a monthly fee of $16, and he pays an additional $0.04 per minute if use. This means that if he used m minutes in a month, the total cost would be

16 + 0.04m

The least he has been charged in a month is $69.52. This means that

16 + 0.04m ≥ 65.92

0.04m ≥ 65.92 - 16

0.04m ≥ 49.92

m ≥ 49.92/0.04

m ≥ 1248 minutes

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3 years ago

Need help pzzzzzzz 9.

Mrac [35]

Answer:

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3 years ago