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3 years ago

6n-3>-18 Solve the inequality

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

Answer:

Step-by-step explanation:

First, you have to isolate it on one side of the equation. Remember that, isolate n on one side of the equation.

6n-3>-18

6n-3+3>-18+3 (Add 3 from both sides.)

-18+3 (Solve.)

-18+3=-15

6n>-15

6n/6>-15/6 (Divide by 6 from both sides.)

-15/6 (Solve.)

-15/6=-5/2

n>-5/2

In conclusion, the correct answer is n>-5/2.

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When you multiply a function by -1 what is the effect on its graph?

vlada-n [284]

Answer:

Step-by-step explanation:

Depends on what you mean by multiplying by - 1. I assume you are not going to multiply the y or f(x) term by - 1.

If that is so, take an example. Suppose you have a graph that is y=x^2

That's a parabola that opens upwards and it has a line going through its focus which is a point on the +y axis.

When you multiply the right hand side by - 1, the graph you get will be y = - x^2.

That opens downward and the focus is on the - y axis.

That means that the effect of the graph is that it flips over the x axis, which I think is the third answer.

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3 years ago

If b=4 units and h=5 units, the area of the triangle is _____<br> units2.

mestny [16]

Answer:

Step-by-step explanation:

Area = 1/2 b h

= 1/2 * 4 * 5

= 10 unit^2.

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2 years ago

Which of the following is the inverse of f(x)=3-x/5?

pshichka [43]

Answer:

-5x+3 OR 5x-3

Step-by-step explanation:

You find the inverse by replacing the x with the y, and solving for y. Doing this actually gives you -5x+3 but in this case, the closest answer would be 5x-3.

UPDATE: -5x + 3 can be written as 3 - 5x lol

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3 years ago

Read 2 more answers

State the number of possible triangles that can be formed using the given measurements.

romanna [79]

Answer: 39) 1 40) 2

41) 1 42) 0

<u>Step-by-step explanation:</u>

39) ∠A = ? ∠B = ? ∠C = 129°

a = ? b = 15 c = 45

Use Law of Sines to find ∠B:

$\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o$

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36° ∠B = 15° ∠C = 129° is the only valid solution.

40) ∠A = 16° ∠B = ? ∠C = ?

a = 15 b = ? c = 19

Use Law of Sines to find ∠C:

$\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o$

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1: ∠A = 16° ∠B = 144° ∠C = 20°

Solution 2: ∠A = 16° ∠B = 4° ∠C = 160°

41) ∠A = ? ∠B = 75° ∠C = ?

a = 7 b = 30 c = ?

Use Law of Sines to find ∠A:

$\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o$

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13° ∠B = 75° ∠C = 92° is the only valid solution.

42) ∠A = ? ∠B = 119° ∠C = ?

a = 34 b = 34 c = ?

Use Law of Sines to find ∠A:

$\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o$

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

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3 years ago

What two numbers added together give you 18.41 percent ?

Kamila [148]

15+ 3.41 this is it hope it helps

3 0

3 years ago