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Airida [17]
3 years ago
15

Write in simplest form

Mathematics
1 answer:
Gnoma [55]3 years ago
4 0

Find the commomon denominator of 6 and 5.

It's 6 · 5 = 30.

\dfrac{5}{6}=\dfrac{5\cdot5}{6\cdot5}=\dfrac{25}{30}\\\\\dfrac{1}{5}=\dfrac{1\cdot6}{5\cdot6}=\dfrac{6}{30}

\left(\dfrac{5}{6}-\dfrac{1}{5}\right)\div\dfrac{4}{5}=\left(\dfrac{25}{30}-\dfrac{6}{30}\right)\div\dfrac{4}{5}=\dfrac{25-6}{30}\div\dfrac{4}{5}=\dfrac{19}{30}\div\dfrac{4}{5}

Divide by fraction is the same like multiply by reciprocal of this fraction:

=\dfrac{19}{30}\cdot\dfrac{5}{4}=\dfrac{19}{6}\cdot\dfrac{1}{4}=\dfrac{19}{24}

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Find polar coordinates of the point whose cartesian coordinates are given. (-2√3 , 2)
gavmur [86]

The  polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

<h3>Polar form of a rectangular coordinate</h3>

The polar form of a rectangular coordinate (x, y) is expressed as (rcos theta, r sin theta)

Given the coordinate (-2√3 , 2)

r = √(-2√3)²+2²

r = √12+4

r = 4

theta = tan^-1(-2/2√3)

theta = tan^-1(-1/√3)

theta = -30 degrees = 210 degrees

The  polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

Learn more on polar coordinate here: brainly.com/question/14965899

#SPJ1

8 0
1 year ago
Point Q is the midpoint of GH¯¯¯¯¯¯ . GQ=2x+3, and GH=5x−5 .<br><br> What is the length of GQ¯¯¯¯¯ ?
AveGali [126]

Point Q is the midpoint of GH

so GQ = QH

Given GQ=2x+3, and GH=5x−5 .

2x + 3 = 5x − 5

3x = 8

x = 8/3

GQ = 2(8/3) +3

GQ = 16/3 + 3

GQ = 16/3 + 9/3

GQ = 25/3

GQ = 8 1/3

3 0
3 years ago
In 2011, the population of deer in a forest was 650.
Jet001 [13]

1::650(1.15)

2: 650(1.15)2

3: 650(1.15) t

8 0
2 years ago
If 2x+ y= 10 and y=3x find the value of both x and y
Marat540 [252]

Given the set of equations:

2x + y = 10

y = 3x

Let's solve for x and y.

Here, let's use substitution method.

Substitute 3x for y in equation 1:

2x + y = 10

2x + 3x = 10

5x = 10

Divide both sides by 5:

\begin{gathered} \frac{5x}{5}=\frac{10}{5} \\  \\ x=2 \end{gathered}

In equation 2, substitute 2 for x to find y.

y = 3x

y = 3(2)

y = 6

Therefore, we have:

x = 2 and y = 6

ANSWER:

x = 2, y = 6

6 0
1 year ago
m∠AOB = 6x + 5, m∠BOC = 4x - 2, m∠AOC = 8x + 21
AnnZ [28]
The sum of angle AOB and angle BOC is equal tot he angle of AOC so

6x+5 +4x-2 = 8x+21

10x+3=8x+21

Subtract three and 8x from both sides

2x=18

Divide by two

x=9

Hope this helped!
6 0
3 years ago
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