The polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)
<h3>Polar form of a rectangular coordinate</h3>
The polar form of a rectangular coordinate (x, y) is expressed as (rcos theta, r sin theta)
Given the coordinate (-2√3 , 2)
r = √(-2√3)²+2²
r = √12+4
r = 4
theta = tan^-1(-2/2√3)
theta = tan^-1(-1/√3)
theta = -30 degrees = 210 degrees
The polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)
Learn more on polar coordinate here: brainly.com/question/14965899
#SPJ1
Point Q is the midpoint of GH
so GQ = QH
Given GQ=2x+3, and GH=5x−5 .
2x + 3 = 5x − 5
3x = 8
x = 8/3
GQ = 2(8/3) +3
GQ = 16/3 + 3
GQ = 16/3 + 9/3
GQ = 25/3
GQ = 8 1/3
Given the set of equations:
2x + y = 10
y = 3x
Let's solve for x and y.
Here, let's use substitution method.
Substitute 3x for y in equation 1:
2x + y = 10
2x + 3x = 10
5x = 10
Divide both sides by 5:

In equation 2, substitute 2 for x to find y.
y = 3x
y = 3(2)
y = 6
Therefore, we have:
x = 2 and y = 6
ANSWER:
x = 2, y = 6
The sum of angle AOB and angle BOC is equal tot he angle of AOC so
6x+5 +4x-2 = 8x+21
10x+3=8x+21
Subtract three and 8x from both sides
2x=18
Divide by two
x=9
Hope this helped!