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barxatty [35]
3 years ago
14

After 3 half lifes how many c-14 atoms would remain

Biology
1 answer:
ipn [44]3 years ago
6 0

Answer:

Halife of C-14 is=14(RAM÷2)

You get=7 but further more let's say after 3 half life as your question stated it may result to decimal something which is impossible (as nucleons never be decimal)

Hence after 3half life it will continue to be 7

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2 years ago
Smart growth is an urban planning theory that promotes the development of suburbs surrounding major city centers.
Lelu [443]

Answer:

False.

Explanation:

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Which of the following describes how polluted water sources would most likely affect one’s personal health?. Answer. Bacteria wo
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3 0
3 years ago
Read 2 more answers
One of your lab partners has followed the recommended procedure of running Gram-positive and Gram-negative control organisms on
andreyandreev [35.5K]

Answer:

Reduced in holding time of decolrization step and also used less Alcohol because decolrization step is important in Gram's staining.The decolorization step must be performed carefully. Otherwise over-decolorization may occur. This step is critical and must be timed correctly otherwise the CV stain will be removed from the Gram-positive cells. If the decolorizing agent is applied on the cell for too long time, the Gram-positive organisms to appear Gram-negative..

Explanation:

Gram' staining is a technique used in microbiology labs to differentiate between Gram's positive and negative

<u>Gram-positive bacteria :</u>Stain dark purple due to retaining the primary dye called CV in the cell wall.

<u>:Gram-negative bacteria </u>Stain red or pink due to retaining the counter staining dye called Safranin or neutral red.

There are four basic step in Gram" staining

1) Application of the Primary Stain to a Heat-Fixed Smear of Bacterial Culture

2)Addition of Gram's Iodine

3)<u>Decolorization with 95% Ethyl Alcohol:</u>Alcohol or acetone dissolves the lipid outer membrane of Gram-negative bacteria, thus leaving the peptidoglycan layer exposed and increases the porosity of the cell wall. The CV-I complex is then washed away from the thin peptidoglycan layer, leaving Gram-negative bacteria colorless.

On the other hand, alcohol has a dehydrating effect on the cell walls of Gram-positive bacteria that causes the pores of the cell wall to shrink. The CV-I complex gets tightly bound into the multi-layered, highly cross-linked Gram-positive cell wall thus staining the cells purple.

The decolorization step must be performed carefully. Otherwise over-decolorization may occur. This step is critical and must be timed correctly otherwise the CV stain will be removed from the Gram-positive cells. If the decolorizing agent is applied on the cell for too long time, the Gram-positive organisms to appear Gram-negative. Under-decolorization occurs when the alcohol is not left on long enough to wash out the CV-I complex from the Gram-negative cells, resulting in Gram-negative bacteria to appear Gram-positive.

7 0
3 years ago
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STatiana [176]

B and C ANSWER...

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