Answer:
151434/358 = 423
Step-by-step explanation:
Every product with non-zero factors can be written as an equivalent division relation.
a·b = c ⇒ a = c/b
Here, we have 35.8 × 4.23 = 151.434. This can be written as the equivalent ...
4.23 = 151.434/35.8
We can multiply this by 100 to get a division relation with a quotient of 423:
423 = 15143.4/35.8
If we want, we can move the decimal points another place to the right to get ...
151434/358 = 423
slope = (6 - 1)/(-2 - 1) = 5/-3 = -5/3
Equation
y - 6 = -5/3 (x + 2)
Hope it helps
Answer:
23.7m
Step-by-step explanation:
Given parameters:
Time taken = 2.2s
Acceleration due to gravity = 10m/s
Unknown:
Depth of the well = ?
Solution:
To solve this problem, we simply apply one of the motion equations;
S = ut +
gt²
where S = depth of the well
u = initial velocity
t = time taken
g = acceleration due to gravity
Input the parameters and solve for S;
Note initial velocity = 0;
S =
x 9.8 x 2.2²
S = 23.7m
Answer:
width = 8 ft & length = 32 ft.
Step-by-step explanation:
let the width be x and length be 4x.
we know, Perimeter = 2(l+b)
now,
2(4x + x) = 80
10x = 80
x = 80/10 = 8
x = 8
therefore,
width = x = 8 ft
length = 4x = 4 × 8 = 32 ft.
hope this helps you !
Answer:

Step-by-step explanation:
Given

Required
Determine the 10th term
Using binomial expansion, we have:

For, the 10th term. n = 9
So, we have:



Apply combination formula







Hence, the 10th term is 