How many bricks each 0.16m2 are required for paving a courtyard of 5.5m long and 4.8m wide?

A 95 percent confidence interval for the mean of a population is to be constructedand must be accurate within 0.3 unit. A prelim

jarptica [38.1K]

Answer:

B. 359

Step-by-step explanation:

Given that:

The margin of error (e) must be within 0.3 unit, The standard deviation (σ) = 2.9 and the the confidence level = 95% = 0.95

α = 1 =0.95 = 0.05

$\frac{\alpha}{2}=\frac{0.05}{2}=0.025$

The z score of 0.025 corresponds to the z score of 0.0475 (0.5 - 0.025) which can be gotten from the normal probability table.

Therefore: $z_\frac{\alpha}{2}= z_{0.025}=1.96$

The formula for the margin of error is given by:

$e=z_{0.025}\frac{\sigma}{\sqrt{n} } \\Substituting:\\0.3=1.96*\frac{2.9}{\sqrt{n} } \\\sqrt{n}=\frac{1.96*2.9}{0.3}\\\sqrt{n} =18.95\\ n=18.95^2=359$

Therefore the smallest sample size (n) is 359

5 0

3 years ago

A bag of marbles contains 6 blue marbles, 2 yellow marbles, 4 red marbles, and 1 green marble. What is the probability of reachi

Mice21 [21]

Total marbles = 13

Number of yellow = 2

probability of getting yellow = 2/13

5 0

3 years ago

Write 3 other fractions that are equivalent to the given fraction. Include simplest Ford of the fraction

noname [10]

11.

$\dfrac{16}{100} =\\1)=\dfrac{160}{1000} \\2)=\dfrac{32}{200} \\3)=\dfrac{4}{25}$

12.

$\dfrac{32}{48}=\\1) =\dfrac{4}{6} \\2)=\dfrac{64}{96} \\3)=\dfrac{2}{3}$

13.

$\dfrac{21}{48} =\\1)=\dfrac{7}{16} \\2)=\dfrac{42}{96} \\3) =\dfrac{210}{480}$

6 0

3 years ago

Can someone help me with my last question

slega [8]

What you need to do is that you plug p=3 into the expression [(5.4p+5)+(8+3.2p)]/2 and you have:
[(5.4*3+5)+(8+3.2*3)]/2
= (21.2+ 17.6)/2
= 38.8/2
= 19.4

The average of the two boys' points is p=3 is 19.4 points~

4 0

3 years ago

Players in any sport who are having great seasons, turning in performances that are much better than anyone might haveanticipa

Sav [38]

Answer:

I pick the reasoning of option A

Step-by-step explanation:

I like the reasoning given in B, however, there are many cases of Athletes that, after reaching the top, maintain supremacy and improve over the years, adapting to their old age. Usually speed and physical resistance are replaced by technique and experience in the case of the top athletes.

I dont like C and D argument too much because being the best in a sport doesnt mean either that you reach the maximum level possible (in many cases you can keep growing) or that you dont have more motivations. Many athletes are super competitive people and they try to improve themselves all the time to reach, and stay, in the top.

I choose option A as answer because people on the cover doesnt neccesarily mean that they are the absolute best. Their performance was way better than their usual performance, and that may be due to either real skill growth, heavy training or a lucky streak. If it is a lucky streak, it is natural for that player's performance to go down into more terrenal levels for him. On the other hand, If he trained heavily, then he might have big injuries on later seasons and his performance wont be able to keep up for long. Thats why 'surprises' (that also sell better due to be a novelty) tend to go downhill after they reach the cover of sports illustrated.

7 0

4 years ago

How many bricks each 0.16m2 are required for paving a courtyard of 5.5m long and 4.8m wide? ​

How many bricks each 0.16m2 are required for paving a courtyard of 5.5m long and 4.8m wide?