100% of the rolls would be less than 13. The highest number on one die is 6, so even if you roll 2 dice the sum of both dice will always be lower than 13.
It's a 1:1 probablility.
The answer should be (exact number- 93/10) (decimal form- 9.3) (mixed number- 9 3/10)
sorry if i’m incorrect
Answer:
![\frac{3}{28}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B28%7D)
Step-by-step explanation:
Probability (P) is calculated as
P = ![\frac{requiredoutcome}{count}](https://tex.z-dn.net/?f=%5Cfrac%7Brequiredoutcome%7D%7Bcount%7D)
The first required outcome is a red sweet from a total of 3 + 5 = 8
P( red) = ![\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7D)
There are now 2 red left and a count of 7, since 1 has been eaten, thus
P( second red ) = ![\frac{2}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B7%7D)
P( red and red ) =
×
=
= ![\frac{3}{28}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B28%7D)
Doug's bar is 50 km away from Ben's bar. let me know if I need to explain.
You can use a calculator for this if you have the graphing kind (I use a Ti-84) and when plugging the equation in, the answers should be b, d, and e