Please help answer this question idk if im right or not

Consider the system of equations given in slope-intercept form. y = −13x + 17, y = 5x - 23 The solution seems to be about (8, 14

bogdanovich [222]

Answer:

The exact solution for this equation would be (2.222, -11.889)

Step-by-step explanation:

Since it told us to use a graphing calculator, I went on to desmos graphing calculator, typed in the equation, then I found out where the two line intersect, and then that was the answer.

4 0

3 years ago

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A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh

Stella [2.4K]

A parabola is a mirror-symmetrical U-shape.

The equation of the parabola is $\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$
The focus is $\mathbf{Focus = (80, -1760)}$
The directrix is $\mathbf{y = \frac{1}{640}}$
The axis of the symmetry of parabola is: $\mathbf{x = 80}$

From the question, we have:

$\mathbf{Vertex: (h,k) = (80,10)}$

$\mathbf{Origin: (x,y) = (0,0)}$

The equation of a parabola is:

$\mathbf{y = a(x - h)^2 + k}$

Substitute the values of origin and vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{0 = a(0 - 80)^2 + 10}$

$\mathbf{0 = a(- 80)^2 + 10}$

$\mathbf{0 = 6400a + 10}$

Collect like terms

$\mathbf{6400a =- 10}$

Solve for a

$\mathbf{a =- \frac{1}{640}}$

Substitute the values of a and the vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

The focus of a parabola is:

$\mathbf{Focus = (h, \frac{k+1}{4a})}$

Substitute the values of a and the vertex in $\mathbf{Focus = (h, \frac{k+1}{4a})}$

$\mathbf{Focus = (80, \frac{10+1}{4 \times -\frac{1}{640}})}$

$\mathbf{Focus = (80, -\frac{11}{\frac{1}{160}})}$

$\mathbf{Focus = (80, -11\times 160)}$

$\mathbf{Focus = (80, -1760)}$

The equation of the directrix is:

$\mathbf{y = -a}$

So, we have:

$\mathbf{y = \frac{1}{640}}$ ----- the directrix

The axis of symmetry is:

$\mathbf{x = -\frac{b}{2a}}$

We have:

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

Expand

$\mathbf{y = -\frac{1}{640}(x^2 -160x + 6400) +10}$

Expand

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x - 10 +10}$

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x }$

A quadratic function is represented as:

$\mathbf{y = ax^2 + bx + c}$

So, we have:

$\mathbf{a = -\frac{1}{640}}$

$\mathbf{b = \frac{1}{4}}$

Recall that:

$\mathbf{x = -\frac{b}{2a}}$

So, we have:

$\mathbf{x = -\frac{1/4}{2 \times -1/640}}$

$\mathbf{x = \frac{1/4}{1/320}}$

This gives

$\mathbf{x = \frac{320}{4}}$

$\mathbf{x = 80}$

Hence, the axis of the symmetry of parabola is: $\mathbf{x = 80}$

Read more about parabola at:

brainly.com/question/21685473

6 0

2 years ago

You can construct congruent triangles if you know which of the following?

S_A_V [24]

The answer is D. SAS, ASA, and SSS show congruent triangles.

4 0

2 years ago

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Michelle purchased a kids table with a square top if the area of the square top is 400 square inches what is the length of one o

worty [1.4K]

400 in² = (20 in)²

The area of a square is the square of the side length.

The length of one of the sides is 20 inches.

7 0

2 years ago

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In the diagram shown overline AD and intersect at point E. overline AB and overline CD are parallel . Given the segment length s

Harrizon [31]

Answer:

11.25

Step-by-step explanation:

Since AB and CD are parallel, ∠D is congruent to ∠A and ∠C is congruent to ∠B. Therefore the two triangles are similar by the AA postulate. Now, the corresponding sides are in proportion

Since AE ↔ DE and AB ↔ CD

So, AE/CD = AB/CD

AE/5 = 9/4

AE = 9(5)/4

= 45/4 = 11.25

8 0

2 years ago