Sea stack sea arch an sea caves are all examples of land features created by

Chemistry

1 answer:

Darya [45]2 years ago

4 0

The correct answer is - wave erosion.

The sea stack, sea arch, and the sea caves, are all land features that have gradually been formed by the influence of the waves, or rather by the erosion that the waves have caused on them.

The sea stack is a land form very close to the coast, and it is manifested by solitary very steep rocks, or as group of very steep rocks, and they have formed because of the wave and wind erosion.

The sea arch is land form that appears as an opening in a cliff, being formed by the the wave refraction where the focus of waves goes on the sides of a headland.

The sea caves are openings deeper into the crust, where the waves managed to erode the softer rocks, and the water to penetrate deeper inside.

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How many moles are in 39.5 grams of Lithium?

Blizzard [7]

Answer:

185.05 g.

Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365 moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).

Molar mass of LiCl = 42.394 g/mole.

mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

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2 years ago

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Identify the ion ratios needed to form neutral compounds from the ions below. The metal ion (cation) is listed first, and the no

Natasha2012 [34]

To figure out the ratios of these compounds, it is important to remember that the charge of these compounds must be <em>neutral</em>.

So in order to make them neutral, you must have specific ratios:

$Na^{+}: Br^{-} =1:1$ ; This is true because they both have a charge of magnitude of 1.

$Al^{3+}: Cl^{-}=1:3$ ; We need 3 chlorine atoms because we need to balance out the charge from the 3+ charge of aluminum - therefore since chlorine has a 1- charge, we need 3 atoms.

$Mg^{2+}: O^{2-}=1:1$ ; The charges of the magnesium (2+) are balanced with the oxygen charge (2-).

$Al^{3+}: O^{2-}=2:3$ ; This is correct because if charges are like this, you must find the least common factor in order to know the ratio. The LCF is 6, therefore, for the atom with a 3+ charge, you need 2 of them, and for the atom with a 2- charge, you need 3 of them. This keeps the charge neutral.

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3 years ago

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