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Free_Kalibri [48]
3 years ago
5

Does anyone know how to do this?

Chemistry
1 answer:
Sloan [31]3 years ago
4 0

Answer

find out the number of moles and use the molar ratio (numbers in front of formulas (in this case they are all 1) to determine how many moles of each product you are going to get theoretically

n=m/M is the equation to use to get moles here

30.8 gm/32.04 g/mol=0.9612 moles of the methanol and also of the formaldehyde so

0.9612 moles of the formaldehyde x molar mass (M) 30.73 g/mol= 29.54 gm which is the theoretical yield you already have the actual yield of 24.7 gm

then divide the actual by the theoretical to get the % yield which is 83.6%

Explanation:

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On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35cl and 86.15 % for 37cl. What
Evgen [1.6K]
<h3>Answer:</h3>

              36.70 amu

<h3>Solution:</h3>

Data Given:

                       Atomic Mass of ³⁵Cl  =  34.9700 amu

                       Natural Abundance of ³⁵Cl  =  13.85 %

                       Atomic Mass of ³⁷Cl  =  36.9700 amu

                       Natural Abundance of ³⁷Cl  =  86.15 %

Formula Used:

Average Atomic Mass  =  [(Atomic Mass of ³⁵Cl × Natural Abundance of ³⁵Cl) + (Atomic Mass of ³⁷Cl × Natural Abundance of ³⁷Cl)] ÷ 100

Putting values,

Average Atomic Mass  =  [(34.9700 × 13.85) + (36.9700 × 86.15)] ÷ 100

Average Atomic Mass  =  [(484.3345) + (3184.9655)] ÷ 100

Average Atomic Mass  =  3669.3 ÷ 100

Average Atomic Mass  =  36.70 amu

8 0
3 years ago
List the number of protons, neutrons, and electrons in titanium<br><br> P-<br><br> N-<br><br> E-
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Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitro
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Answer : The partial pressure of O_2 is, 222.93 torr

Explanation :  

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First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{168.6min}

k=4.11\times 10^{-3}min^{-1}

Now we have to calculate the partial pressure of O_2

The balanced chemical reaction is:

                           2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Initial pressure   760                0             0

At eqm.             (760-2x)            4x            x

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{P_o}{P_t}

where,

k = rate constant

t = time passed by the sample  = 215 min

a = initial pressure of N_2O_5 = 760 torr

a - x = pressure of N_2O_5 at equilibrium = (760-2x) torr

Now put all the given values in above equation, we get:

215=\frac{2.303}{4.11\times 10^{-3}}\log\frac{760}{760-2x}

x=222.93torr

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