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Free_Kalibri [48]
3 years ago
5

Does anyone know how to do this?

Chemistry
1 answer:
Sloan [31]3 years ago
4 0

Answer

find out the number of moles and use the molar ratio (numbers in front of formulas (in this case they are all 1) to determine how many moles of each product you are going to get theoretically

n=m/M is the equation to use to get moles here

30.8 gm/32.04 g/mol=0.9612 moles of the methanol and also of the formaldehyde so

0.9612 moles of the formaldehyde x molar mass (M) 30.73 g/mol= 29.54 gm which is the theoretical yield you already have the actual yield of 24.7 gm

then divide the actual by the theoretical to get the % yield which is 83.6%

Explanation:

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Answer:

a and d

Explanation:

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Based on your knowledge of intermolecular forces and trends, select the statement that is most accurately compares HF and HCl.
tangare [24]

Answer:

(A) The intermolecular attraction between HF molecules are stronger than between HCl molecules mainly to due hydrogen bonding.

Explanation:

Since Flourine is highly electronegative and as such, when it bonds with Hydrogen it forms a hydrogen bond. Whereas the HCL molecule  is a polar molecule whose inter-molecular forces are dipole dipole interactions. Although a Hydrogen bond is a type of dipole dipole interaction it is stronger than the traditional dipole dipole forces and London dispersion forces. HF also has a shorter bond length which makes the bond and inter-molecular forces  stronger as compared to HCL.

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77julia77 [94]

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Explanation:

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The volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.

Explanation:

As per Boyle's law, the volume occupied by gas particles will be inversely proportional to the pressure experienced by those particles at constant temperature.

V=\frac{1}{P}

So in the present problem, the volume of gas at pressure P₁ = 99.6 kPa is given as V₁ = 4.23 L. The temperature is kept constant at 24°C. Then, if the pressure is decreased to 93.3 kPa, then the volume is tend to increase due to Boyle's law.

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Then using Boyle's law, P_{1} V_{1} = P_{2}  V_{2}

Then, V_{2}=\frac{P_{1} V_{1} }{P_{2} }

So, V_{2}=\frac{99.6*1000*4.23}{93.3*1000}=4.52 L

Thus, the volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.

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