KBr + H2O = KOH + Br2 + H2
So we know that we need a 2 on the left of kbr so it would equal the right Br.
=2KBr
now put a 2 in front of KOH since we need a 2k on right side
Now we put a 2 infront of H2O which wil make 4 h's and 2 o's
2h2o
now it is balanced
2KBr + 2H2O = 2KOH + Br2 + H2
Actual Resources: are those which have been surveyed, their quantity and quality determined and are being used in present times.
Potential Resources: <span>They can exist in a region and can be used in the future.</span>
<u>Given:</u><u> </u>
Mass of Nitrogen (N₂) gas = 75 grams
<u>Finding the number of moles of N₂:</u><u> </u>
We know that the molar mass of N₂ is 28 grams/mole
Number of moles = Given mass / Molar mass
Number of moles = 75 / 28
Number of moles = 2.68 moles
Hence, there are 2.68 moles in 75 grams of Nitrogen Gas