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The co ordinates of P' is (-7,-2) and Q' is (-16, -8)
<u><em>Explanation</em></u>
PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.
According to the graph, the coordinates of P is (-7, -2) and Q is (2, 4)
When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>
Suppose, the co ordinate of Q' is (x, y)
Now according to the mid-point formula, the coordinate of P or P' will be:
, which is actually at (-7, -2)
Thus.....
![\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B2%7D%7B2%7D%3D-7%5C%5C%20%5C%5C%20x%2B2%3D-14%5C%5C%20%5C%5C%20x%3D%20-16%5C%5C%20%5C%5C%20and%5C%5C%20%5C%5C%20%5Cfrac%7By%2B4%7D%7B2%7D%3D%20-2%5C%5C%20%5C%5C%20y%2B4%3D%20-4%5C%5C%20%5C%5C%20y%3D%20-8)
So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)
Answer:
9
Step-by-step explanation:
you want the trinomial (x*x - 6x + __ ) to be written as a binomial squared.
So we would need to realize that the constant would be equal to (-6/2)^2 =(-3)^2 = 9
We have completed the square.
f(x) = 4*( x - 3)^2 + 20 is now in Vertex Form